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EC number: 201-051-3 | CAS number: 77-71-4
Vapour pressure
Administrative data
- Endpoint:
- vapour pressure
- Type of information:
- experimental study
- Adequacy of study:
- key study
- Study period:
- Testing was conducted between 03 November 2009 and 17 November 2009.
- Reliability:
- 1 (reliable without restriction)
- Rationale for reliability incl. deficiencies:
- other: Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results.
Data source
Reference
- Reference Type:
- study report
- Title:
- Unnamed
- Year:
- 2 010
- Report date:
- 2010
Materials and methods
Test guideline
- Qualifier:
- according to guideline
- Guideline:
- EU Method A.4 (Vapour Pressure)
- Deviations:
- no
- GLP compliance:
- yes (incl. QA statement)
- Remarks:
- Date of inspection: 15-09-2009 Date of Signature:26-11-2009
- Type of method:
- other: vapour pressure balance
Test material
- Reference substance name:
- DMH
- IUPAC Name:
- DMH
- Details on test material:
- Sponsor's identification: DMH
Description: white crystalline solid
Batch number: N5439431
Date received: 24 February 2006
Storage conditions: room temperature in the dark
Constituent 1
Results and discussion
Vapour pressure
- Temp.:
- 25 °C
- Vapour pressure:
- 0 Pa
- Remarks on result:
- other: The vapour pressure of the test material has been determined to be 3.8 x 10-4 Pa at 25ºC.
Transition / decomposition
- Transition / decomposition:
- no
Any other information on results incl. tables
Results
Run1
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
101 |
374.15 |
0.002672725 |
927.10 |
9.271E-07 |
1.287052322 |
0.109596202 |
102 |
375.15 |
0.002665600 |
996.02 |
9.960E-07 |
1.382730939 |
0.140737680 |
103 |
376.15 |
0.002658514 |
1095.47 |
1.095E-06 |
1.520793018 |
0.182070110 |
104 |
377.15 |
0.002651465 |
1187.39 |
1.187E-06 |
1.648401528 |
0.217063008 |
105 |
378.15 |
0.002644453 |
1316.91 |
1.317E-06 |
1.828208470 |
0.262025717 |
106 |
379.15 |
0.002637479 |
1413.14 |
1.413E-06 |
1.961800364 |
0.292654811 |
107 |
380.15 |
0.002630541 |
1540.30 |
1.540E-06 |
2.138331023 |
0.330074937 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.
Slope -5309.481
Standard deviation in slope 91.611
Intercept 14.297
Standard deviation in intercept 0.243
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -5309.481/temp(K) + 14.297
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.511.
Run 1 - Graph of Log10Vapour Pressure vs Reciprocal Temperature (please see attached Run 1 to Run 4 Graphs of log10Vapour Pressure vs Reciprocal Temperature)
Run 2
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
101 |
374.15 |
0.002672725 |
927.73 |
9.277E-07 |
1.287926923 |
0.109891222 |
102 |
375.15 |
0.002665600 |
999.71 |
9.997E-07 |
1.387853604 |
0.142343658 |
103 |
376.15 |
0.002658514 |
1092.33 |
1.092E-06 |
1.516433893 |
0.180823483 |
104 |
377.15 |
0.002651465 |
1185.98 |
1.186E-06 |
1.646444086 |
0.216546987 |
105 |
378.15 |
0.002644453 |
1286.37 |
1.286E-06 |
1.785811126 |
0.251835524 |
106 |
379.15 |
0.002637479 |
1392.65 |
1.393E-06 |
1.933354995 |
0.286311605 |
107 |
380.15 |
0.002630541 |
1516.75 |
1.517E-06 |
2.105637589 |
0.323383625 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.
Slope -5076.768
Standard deviation in slope 36.058
Intercept 13.677
Standard deviation in intercept 0.096
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -5076.768/temp(K) + 13.677
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.350.
Run 2 - Graph of Log10Vapour Pressure vs Reciprocal Temperature (please see attached Run 1 to Run 4 Graphs of log10Vapour Pressure vs Reciprocal Temperature)
Run 3
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
101 |
374.15 |
0.002672725 |
927.10 |
9.271E-07 |
1.287052322 |
0.109596202 |
102 |
375.15 |
0.002665600 |
1001.36 |
1.001E-06 |
1.390144227 |
0.143059860 |
103 |
376.15 |
0.002658514 |
1089.19 |
1.089E-06 |
1.512074769 |
0.179573267 |
104 |
377.15 |
0.002651465 |
1199.01 |
1.199E-06 |
1.664533065 |
0.221292426 |
105 |
378.15 |
0.002644453 |
1286.92 |
1.287E-06 |
1.786574667 |
0.252021172 |
106 |
379.15 |
0.002637479 |
1399.25 |
1.399E-06 |
1.942517486 |
0.288364937 |
107 |
380.15 |
0.002630541 |
1520.60 |
1.521E-06 |
2.110982376 |
0.324484607 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.
Slope -5119.079
Standard deviation in slope 60.228
Intercept 13.790
Standard deviation in intercept 0.160
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -5119.079/temp(K) + 13.790
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.379.
Run 3 - Graph of Log10Vapour Pressure vs Reciprocal Temperature (please see attached Run 1 to Run 4 Graphs of log10Vapour Pressure vs Reciprocal Temperature)
Run 4
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
101 |
374.15 |
0.002672725 |
911.72 |
9.117E-07 |
1.265700941 |
0.102331103 |
102 |
375.15 |
0.002665600 |
996.73 |
9.967E-07 |
1.383716601 |
0.141047151 |
103 |
376.15 |
0.002658514 |
1077.18 |
1.077E-06 |
1.495401812 |
0.174757903 |
104 |
377.15 |
0.002651465 |
1182.21 |
1.182E-06 |
1.641210360 |
0.215164250 |
105 |
378.15 |
0.002644453 |
1273.66 |
1.274E-06 |
1.768166390 |
0.247523131 |
106 |
379.15 |
0.002637479 |
1393.75 |
1.394E-06 |
1.934882077 |
0.286654502 |
107 |
380.15 |
0.002630541 |
1496.27 |
1.496E-06 |
2.077206102 |
0.317479590 |
108 |
381.15 |
0.002623639 |
1652.39 |
1.652E-06 |
2.293940660 |
0.360582179 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.
Slope -5191.484
Standard deviation in slope 57.608
Intercept 13.978
Standard deviation in intercept 0.153
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -5191.484/temp(K) + 13.978
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.434.
Run 4- Graph of Log10Vapour Pressure vs Reciprocal Temperature (please see attached Run 1 to Run 4 Graphs of log10Vapour Pressure vs Reciprocal Temperature)
Summary of Results
Run |
Log10[Vp(25ºC)] |
1 |
-3.511 |
2 |
-3.350 |
3 |
-3.379 |
4 |
-3.434 |
Mean |
-3.418 |
Vapour Pressure |
3.8 x 10-4Pa |
Applicant's summary and conclusion
- Conclusions:
- The vapour pressure of the test material has been determined to be 3.8 x 10-4 Pa at 25ºC.
- Executive summary:
Method
The vapour pressure was determined using a vapour pressure balance withasurents being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008.
Procedure
The vapour pressure was determined using a vapour pressure balance. The temperature of the sample was controlled electronically. The mass and temperature readings were recorded automatically into a computer file.
A diagram of the cross-section of the vapour pressure balance is represented in attached Figure 4.1. After evacuating the system, opening the shutter above the sample oven causes the escaping vapour jet to be directed at the scale pan. The difference in mass readings with the orifice covered and uncovered is proportional to the vapour pressure at the given oven temperature.
A sequence of runs was started after a sample of test material had been under vacuum for approximately 68 hours. Temperature and pressure readings were taken between 100 and 110 ºC with a one hour dwell at 100 ºC between runs.Summary of Results
The test material did not change in appearance under the conditions used in the determination.Run
Log10[Vp(25ºC)]
1
-3.511
2
-3.350
3
-3.379
4
-3.434
Mean
-3.418
Vapour Pressure
3.8 x 10-4Pa
Discussion
The unshaded points on the graphshave not been used when plotting the line. It is quite common for the first point of a run to be non linear as the system equilibrates after the dwell time.
Conclusion
The vapour pressure of the test material has been determined to be 3.8 x 10-4 Pa at 25ºC.
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