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Physical & Chemical properties

Vapour pressure

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Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
31 Oct - 02 Nov 2017
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study
Qualifier:
according to
Guideline:
EU Method A.4 (Vapour Pressure)
Version / remarks:
May 2008
Qualifier:
according to
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Version / remarks:
March 23, 2006
Qualifier:
according to
Guideline:
EPA OPPTS 830.7950 (Vapor Pressure)
Version / remarks:
August 1996
GLP compliance:
yes (incl. certificate)
Remarks:
National Good Laboratory Practice (GLP) Compliance Monitoring Authority (NGCMA), Department of Science and Technology, Government of India
Type of method:
effusion method: isothermal thermogravimetry
Temp.:
25 °C
Vapour pressure:
0 Pa

Final results

Replications

log10 Vp (Pa) at 25 °C

I

-17.92

II

-7.96

III

-15.74

Mean

-13.87

Vapour Pressure (Antilog)

1.35 × 10-14

 

 

Detailed results and calculation for replication I

Temperature

Mass of Test Item

Mass Difference

Vapour Pressure

log10 Vp

°C

K

Reciprocal

1/K

mg

mg

kg

Pa

90

363.15

0.002753683

35.1152

-

-

-

-

91

364.15

0.002746121

35.1151

0.0001

0.0000000001

0.000013860

-4.86

92

365.15

0.002738601

35.1150

0.0002

0.0000000002

0.000027720

-4.56

93

366.15

0.002731121

35.1148

0.0004

0.0000000004

0.000055441

-4.26

94

367.15

0.002723682

35.1147

0.0005

0.0000000005

0.000069301

-4.16

95

368.15

0.002716284

35.1145

0.0007

0.0000000007

0.000097021

-4.01

96

369.15

0.002708926

35.1142

0.0010

0.0000000010

0.000138602

-3.86

97

370.15

0.002701607

35.1137

0.0015

0.0000000015

0.000207903

-3.68

98

371.15

0.002694328

35.1133

0.0019

0.0000000019

0.000263343

-3.58

99

372.15

0.002687089

35.1127

0.0025

0.0000000025

0.000346504

-3.46

100

373.15

0.002679887

35.1119

0.0033

0.0000000033

0.000457386

-3.34

 

Vapour pressure curve: reciprocal temperature (1/K) versus log10 Vp(Pa)

- Intercept with y -axis = 54.99

- Slope of the line = -21737.81

- Correlation co-efficient or 'r' value = -0.987

 

Calculation of Vapour Pressure at 25 °C (298.15 K):

log10 Vp(Pa) = (Slope / Temperature (K)) + Intercept = (-21737.81 / 298.15) + 54.99 =-17.92

 

 

Detailed results and calculation for replication II

Temperature

Mass of Test Item

Mass Difference

Vapour Pressure

log10 Vp

°C

K

Reciprocal

1/K

mg

mg

kg

Pa

90

363.15

0.002753683

44.0682

-

-

-

-

91

364.15

0.002746121

44.0657

0.0025

0.0000000025

0.000346504

-3.46

92

365.15

0.002738601

44.0652

0.0030

0.0000000030

0.000415805

-3.38

93

366.15

0.002731121

44.0647

0.0035

0.0000000035

0.000485106

-3.31

94

367.15

0.002723682

44.0643

0.0039

0.0000000039

0.000540547

-3.27

95

368.15

0.002716284

44.0636

0.0046

0.0000000046

0.000637568

-3.20

96

369.15

0.002708926

44.0631

0.0051

0.0000000051

0.000706869

-3.15

97

370.15

0.002701607

44.0625

0.0057

0.0000000057

0.000790030

-3.10

98

371.15

0.002694328

44.062

0.0062

0.0000000062

0.000859331

-3.07

99

372.15

0.002687089

44.0612

0.0070

0.0000000070

0.000970212

-3.01

100

373.15

0.002679887

44.0600

0.0082

0.0000000082

0.001136534

-2.94

 

Vapour pressure curve: reciprocal temperature (1/K) versus log10 Vp(Pa)

- Intercept with y -axis = 16.99

- Slope of the line = -7439.02

- Correlation co-efficient or 'r' value = -0.996

 

Calculation of Vapour Pressure at 25 °C (298.15 K):

log10 Vp(Pa) = (Slope / Temperature (K)) + Intercept = (-7439.02 / 298.15) + 16.99 =-7.96

 

 

Detailed results and calculation for replication III

Temperature

Mass of Test Item

Mass Difference

Vapour Pressure

log10 Vp

°C

K

Reciprocal

1/K

mg

mg

kg

Pa

90

363.15

0.002753683

29.6945

-

-

-

-

91

364.15

0.002746121

29.6942

0.0003

0.0000000003

0.000041581

-4.38

92

365.15

0.002738601

29.6939

0.0006

0.0000000006

0.000083161

-4.08

93

366.15

0.002731121

29.6936

0.0009

0.0000000009

0.000124742

-3.90

94

367.15

0.002723682

29.6931

0.0014

0.0000000014

0.000194042

-3.71

95

368.15

0.002716284

29.6927

0.0018

0.0000000018

0.000249483

-3.60

96

369.15

0.002708926

29.6920

0.0025

0.0000000025

0.000346504

-3.46

97

370.15

0.002701607

29.6913

0.0032

0.0000000032

0.000443525

-3.35

98

371.15

0.002694328

29.6903

0.0042

0.0000000042

0.000582127

-3.23

99

372.15

0.002687089

29.6895

0.0050

0.0000000050

0.000693008

-3.16

100

373.15

0.002679887

29.6880

0.0065

0.0000000065

0.000900911

-3.05

 

Vapour pressure curve: reciprocal temperature (1/K) versus log10 Vp(Pa)

- Intercept with y -axis = 47.81

- Slope of the line = -18947.04

- Correlation co-efficient or 'r' value = -0.984

 

Calculation of Vapour Pressure at 25 °C (298.15 K):

log10 Vp(Pa) = (Slope / Temperature (K)) + Intercept = (-18947.04 / 298.15) + 47.81 =-15.74

Description of key information

OECD guideline, GLP-compliant study available. Melting point was determined using effusion method (isothermal thermogravimetry). Vapour pressure was 1.35 x 10E-14 at 25°C.

Key value for chemical safety assessment

Vapour pressure:
0 Pa
at the temperature of:
25 °C

Additional information