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Diss Factsheets

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Experimental Starting Date: 17 December 2012 Experimental Completion Date: 19 December 2012
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: see 'Remark'
Remarks:
Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results. The study report was conclusive, done to a valid guideline and the study was conducted under GLP conditions.

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2013
Report date:
2013

Materials and methods

Test guideline
Qualifier:
according to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Test material form:
liquid
Specific details on test material used for the study:
Identification: Hydroxybutyl Methacrylate
Description: clear colorless liquid
Batch: 57821 + MKBH4325V
Purity: 98.5%
Expiry / Retest Date: 02 October 2013
Storage Conditions: approximately 4 °C in the dark

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
10 Pa
Transition / decomposition
Transition / decomposition:
no

Any other information on results incl. tables

Results

Recorded temperatures, mass differences and the resulting calculated values of vapor pressure are shown in the following tables. Please see the graphs in Attachment 2 of this Summary.

Run 1

 

Table 3.1 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

110.73

1.107E-07

0.153721609

-0.813265079

-9

264.15

0.003785728

117.72

1.177E-07

0.163425520

-0.786680125

-8

265.15

0.003771450

131.69

1.317E-07

0.182819459

-0.737977581

-7

266.15

0.003757280

151.86

1.519E-07

0.210820586

-0.676086983

-6

267.15

0.003743215

177.32

1.773E-07

0.246165589

-0.608772656

-5

268.15

0.003729256

207.57

2.076E-07

0.288160339

-0.540365793

-4

269.15

0.003715400

235.23

2.352E-07

0.326559506

-0.486037670

-2

271.15

0.003687996

282.16

2.822E-07

0.391710369

-0.407034932

-1

272.15

0.003674444

325.59

3.256E-07

0.452002336

-0.344859321

0

273.15

0.003660992

381.30

3.813E-07

0.529342089

-0.276263573

 

A plot of log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

 

Slope  -3.94 x 103
Standard deviation in slope   101

 

Intercept         14.1
Standard deviation in intercept         0.378

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.94 x 103/temp(K) + 14.1

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.924.

Run 2

 

Table 3.2 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

84.47

8.447E-08

0.117266001

-0.930827885

-9

264.15

0.003785728

91.56

9.156E-08

0.127108738

-0.895824595

-8

265.15

0.003771450

106.03

1.060E-07

0.147196805

-0.832101617

-7

266.15

0.003757280

117.52

1.175E-07

0.163147868

-0.787418596

-5

268.15

0.003729256

158.05

1.581E-07

0.219413892

-0.658735879

-4

269.15

0.003715400

180.92

1.809E-07

0.251163311

-0.600043800

-3

270.15

0.003701647

215.96

2.160E-07

0.299807809

-0.523157060

-2

271.15

0.003687996

244.42

2.444E-07

0.339317580

-0.469393639

-1

272.15

0.003674444

282.76

2.828E-07

0.392543323

-0.406112406

0

273.15

0.003660992

327.99

3.280E-07

0.455334151

-0.341669776

 

A plot of log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

 

Slope  -4.33 x 103
Standard deviation in slope   89.1

 

Intercept         15.5
Standard deviation in intercept         0.332

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -4.33 x 103/temp(K) + 15.5

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.977.

Run 3

 

Table 3.3 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

76.18

7.618E-08

0.105757357

-0.975689410

-9

264.15

0.003785728

91.26

9.126E-08

0.126692261

-0.897249914

-8

265.15

0.003771450

96.55

9.655E-08

0.134036136

-0.872778101

-7

266.15

0.003757280

110.93

1.109E-07

0.153999260

-0.812481366

-6

267.15

0.003743215

136.39

1.364E-07

0.189344263

-0.722747849

-5

268.15

0.003729256

157.15

1.572E-07

0.218164462

-0.661215993

-4

269.15

0.003715400

175.13

1.751E-07

0.243125308

-0.614169831

-3

270.15

0.003701647

213.57

2.136E-07

0.296489876

-0.527990131

-2

271.15

0.003687996

244.22

2.442E-07

0.339039929

-0.469749152

-1

272.15

0.003674444

279.16

2.792E-07

0.387545600

-0.411677189

0

273.15

0.003660992

318.40

3.184E-07

0.442020774

-0.354557320

 

A plot of log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

 

Slope  -4.53 x 103
Standard deviation in slope   95.5

 

Intercept         16.2
Standard deviation in intercept         0.356

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -4.53 x 103/temp(K) + 16.2

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 1.04.

Run 4

 

Table 3.4 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

71.99

7.199E-08

0.099940564

-1.000258205

-9

264.15

0.003785728

83.17

8.317E-08

0.115461268

-0.937563677

-8

265.15

0.003771450

97.85

9.785E-08

0.135840869

-0.866969549

-7

266.15

0.003757280

109.93

1.099E-07

0.152611004

-0.816414151

-6

267.15

0.003743215

132.79

1.328E-07

0.184346541

-0.734365008

-5

268.15

0.003729256

153.86

1.539E-07

0.213597099

-0.670404651

-4

269.15

0.003715400

178.32

1.783E-07

0.247553845

-0.606330323

-3

270.15

0.003701647

201.08

2.011E-07

0.279150556

-0.554161502

-2

271.15

0.003687996

241.12

2.411E-07

0.334736335

-0.475297144

-1

272.15

0.003674444

277.46

2.775E-07

0.385185565

-0.414329997

0

273.15

0.003660992

321.20

3.212E-07

0.445907891

-0.350754842

 

A plot of log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

 

Slope  -4.68 x 103
Standard deviation in slope   42.6

 

Intercept         16.8
Standard deviation in intercept         0.159

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -4.68 x 103/temp(K) + 16.8

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 1.08.

Summary of Results

 

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

 

Table 3.5 – Summary of Vapor Pressure Data

 

Run

Log10[Vp(25 ºC)]

1

0.924

2

0.977

3

1.04

4

1.08

Mean

1.006

Vapor Pressure

10.1 Pa

 

The test item did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:
The vapor pressure of the test item has been determined to be 10 Pa at 25 ºC.
Executive summary:

The determination was carried out using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008.

 

Instrument:                             Vapor pressure balance.

Summary of Results

 

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

 

Table 3.5 – Summary of Vapor Pressure Data

 

Run

Log10[Vp(25 ºC)]

1

0.924

2

0.977

3

1.04

4

1.08

Mean

1.006

Vapor Pressure

10.1 Pa

 

The test item did not change in appearance under the conditions used in the determination.

 

 

Discussion

A total of four runs were completed for the main sequence. Equilibrium with regard to vapor pressure was assessed to have been reached over the four runs. Thus all four runs have been used to calculate the definitive vapor pressure value for the test item.

 

The un-shaded points on Runs 1 and 2 have not been used as they are considered erroneous possible due to external interference (vibration) of the balance.

 

Conclusion

The vapor pressure of the test item has been determined to be 10 Pa at 25 ºC.