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EC number: 701-350-3 | CAS number: -
Vapour pressure
Administrative data
- Endpoint:
- vapour pressure
- Type of information:
- experimental study
- Adequacy of study:
- key study
- Study period:
- Experimental starting date: 29 January 2019 Experimental completion date: 28 February 2019
- Reliability:
- 1 (reliable without restriction)
Data source
Reference
- Reference Type:
- study report
- Title:
- Unnamed
- Year:
- 2 019
- Report date:
- 2019
Materials and methods
Test guidelineopen allclose all
- Qualifier:
- according to guideline
- Guideline:
- EU Method A.4 (Vapour Pressure)
- Deviations:
- no
- Qualifier:
- according to guideline
- Guideline:
- OECD Guideline 104 (Vapour Pressure Curve)
- Deviations:
- no
- GLP compliance:
- yes
- Type of method:
- effusion method: vapour pressure balance
Test material
- Reference substance name:
- 3-sec-[C15-18-(branched and linear)-alk-2-enyl]pyrrolidine-2,5-dione
- EC Number:
- 701-350-3
- Molecular formula:
- Not possible to assign, UVCB
- IUPAC Name:
- 3-sec-[C15-18-(branched and linear)-alk-2-enyl]pyrrolidine-2,5-dione
- Test material form:
- liquid
- Details on test material:
- - Appearance: brown liquid
- Storage: room temperature, in the dark
Constituent 1
- Specific details on test material used for the study:
- Identification: X-16151
Chemical Name: Long chain alkenyl heterocycle
Appearance/physical state: Amber viscous liquid
Batch: R18 13101
Purity: UVCB - 100%
Expiry Date: 02 August 2020
Storage Conditions: Room temperature in the dark
Results and discussion
Vapour pressure
- Key result
- Temp.:
- 25 °C
- Vapour pressure:
- 0 Pa
Any other information on results incl. tables
Results
Graphs of Log10Vapor Pressure vs Reciprocal Temperature Runs 6 to 8 are shown in Attachment 2 of this Summary.
Recorded temperatures, mass differences and the resulting calculated values of vapor pressure are shown in the following tables:
Run 6
Table1– Vapor Pressure Data
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
110 |
383.15 |
0.002610 |
62.06 |
6.206e-08 |
0.08616 |
-1.06469 |
111 |
384.15 |
0.002603 |
59.95 |
5.995e-08 |
0.08323 |
-1.07972 |
112 |
385.15 |
0.002596 |
68.71 |
6.871e-08 |
0.09539 |
-1.02050 |
113 |
386.15 |
0.002590 |
89.90 |
8.990e-08 |
0.12480 |
-0.90379 |
114 |
387.15 |
0.002583 |
84.08 |
8.408e-08 |
0.11672 |
-0.93285 |
115 |
388.15 |
0.002576 |
90.85 |
9.085e-08 |
0.12612 |
-0.89922 |
116 |
389.15 |
0.002570 |
103.43 |
1.034e-07 |
0.14359 |
-0.84288 |
117 |
390.15 |
0.002563 |
105.04 |
1.050e-07 |
0.14582 |
-0.83618 |
118 |
391.15 |
0.002557 |
122.72 |
1.227e-07 |
0.17037 |
-0.76861 |
119 |
392.15 |
0.002550 |
140.41 |
1.404e-07 |
0.19493 |
-0.71012 |
120 |
393.15 |
0.002544 |
156.59 |
1.566e-07 |
0.21739 |
-0.66276 |
A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-6.14 x 103 |
Standard error in slope: |
436
|
Intercept: |
14.9 |
Standard error in intercept: |
1.13 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -6.14 x 103/temp(K) + 14.9
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -5.66.
Run 7
Table2– Vapor Pressure Data
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
110 |
383.15 |
0.002610 |
61.03 |
6.103e-08 |
0.08473 |
-1.07196 |
111 |
384.15 |
0.002603 |
62.65 |
6.265e-08 |
0.08697 |
-1.06063 |
112 |
385.15 |
0.002596 |
72.51 |
7.251e-08 |
0.10066 |
-0.99714 |
113 |
386.15 |
0.002590 |
79.77 |
7.977e-08 |
0.11074 |
-0.95570 |
114 |
387.15 |
0.002583 |
89.94 |
8.994e-08 |
0.12486 |
-0.90358 |
115 |
388.15 |
0.002576 |
92.99 |
9.299e-08 |
0.12909 |
-0.88911 |
116 |
389.15 |
0.002570 |
103.82 |
1.038e-07 |
0.14413 |
-0.84125 |
117 |
390.15 |
0.002563 |
121.99 |
1.220e-07 |
0.16935 |
-0.77121 |
118 |
391.15 |
0.002557 |
133.80 |
1.338e-07 |
0.18575 |
-0.73107 |
119 |
392.15 |
0.002550 |
137.44 |
1.374e-07 |
0.19080 |
-0.71942 |
120 |
393.15 |
0.002544 |
149.66 |
1.497e-07 |
0.20777 |
-0.68242 |
A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-6.25 x 103 |
Standard error in slope: |
222
|
Intercept: |
15.2 |
Standard error in intercept: |
0.573 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -6.25 x 103/temp(K) + 15.2
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -5.74.
Run 8
Table3– Vapor Pressure Data
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
110 |
383.15 |
0.002610 |
58.73 |
5.873e-08 |
0.08153 |
-1.08868 |
111 |
384.15 |
0.002603 |
68.31 |
6.831e-08 |
0.09483 |
-1.02305 |
112 |
385.15 |
0.002596 |
70.52 |
7.052e-08 |
0.09790 |
-1.00922 |
113 |
386.15 |
0.002590 |
75.41 |
7.541e-08 |
0.10469 |
-0.98009 |
114 |
387.15 |
0.002583 |
84.52 |
8.452e-08 |
0.11734 |
-0.93055 |
115 |
388.15 |
0.002576 |
96.06 |
9.606e-08 |
0.13336 |
-0.87497 |
116 |
389.15 |
0.002570 |
99.73 |
9.973e-08 |
0.13845 |
-0.85871 |
117 |
390.15 |
0.002563 |
114.78 |
1.148e-07 |
0.15934 |
-0.79768 |
118 |
391.15 |
0.002557 |
121.47 |
1.215e-07 |
0.16863 |
-0.77307 |
119 |
392.15 |
0.002550 |
153.42 |
1.534e-07 |
0.21299 |
-0.67164 |
120 |
393.15 |
0.002544 |
138.64 |
1.386e-07 |
0.19247 |
-0.71564 |
A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-6.09 x 103 |
Standard error in slope: |
326
|
Intercept: |
14.8 |
Standard error in intercept: |
0.839 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -6.09 x 103/temp(K) + 14.8
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -5.62.
The values of vapor pressure at 25 °C, extrapolated from each graph, are summarized in the following table:
Table 4 Summary of Vapor Pressure Data
Run |
Log10[Vp(25 ºC)] |
6 |
-5.66 |
7 |
-5.74 |
8 |
-5.62 |
Mean |
-5.67 |
Vapor Pressure |
2.13 x 10-6Pa |
Applicant's summary and conclusion
- Conclusions:
- The vapor pressure of the test item has been determined to be 2.1 E-6 Pa at 25 ºC.
- Executive summary:
The determination was carried out using a procedure designed to be compatible with Method A.4 Vapour Pressure of Commission Regulation (EC)
No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.
Discussion
The test item did not change in appearance under the conditions used in the determination.
A total of 8 runs were completed for the main sequence. Equilibrium with regard to vapor pressure has been assessed to have been reached over the final 3 runs; thus the final 3 runs have been used to calculate the vapor pressure.
The results may represent rounded values obtained by calculations based on the exact raw data.
Conclusion
The vapor pressure of the test item has been determined to be 2.1 x 10-6Pa at 25 ºC.
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