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EC number: 481-740-5 | CAS number: 848301-67-7
Vapour pressure
Administrative data
- Endpoint:
- vapour pressure
- Type of information:
- experimental study
- Adequacy of study:
- key study
- Study period:
- June 2005
- Reliability:
- 1 (reliable without restriction)
- Rationale for reliability incl. deficiencies:
- other: Study conducted to GLP and in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not effect the quality of the relevant results.
Data source
Reference
- Reference Type:
- study report
- Title:
- Unnamed
- Year:
- 2 006
- Report date:
- 2006
Materials and methods
Test guideline
- Qualifier:
- according to guideline
- Guideline:
- EU Method A.4 (Vapour Pressure)
- Deviations:
- no
- GLP compliance:
- yes (incl. QA statement)
- Type of method:
- effusion method: vapour pressure balance
Test material
- Reference substance name:
- -
- EC Number:
- 481-740-5
- EC Name:
- -
- Cas Number:
- 848301-67-7
- Molecular formula:
- main general molecular formula: CnH(2n+2)
- IUPAC Name:
- 2,2,3,4,4,5,6-heptamethylheptane; 2,2,8-trimethyltetradecane; 2,2-dimethyldodecane; 2,2-dimethyltetradecane; 2-methyltetradecane; 3,5,7-triethyldecane; 4-ethyldodecane; 4-propyldodecane; 5,5-dipropylnonane; 5,7-dimethyl-4-propylundecane; 5-butyl-5-propyldecane; 5-butyl-5-propylnonane; 5-ethyl-5-propylnonane; 5-ethyl-7-methyl-4-propylundecane; 5-propyltridecane; 6-butyl-6-methyldodecane; 6-butyldodecane; 6-butylundecane; 7-methyl-4-propylundecane; 8-methyl-5-propyltridecane; 9-butyl-6-propylhexadecane; heptadecane; hexacosane; hexadecane; octane; pentadecane; tetradecane
- Details on test material:
- - Name of test material (as cited in study report): Distillates (Fischer-Tropsch), C8-26 branched and linear
- Substance type: Organic
- Physical state: Clear colorless liquid
- Analytical purity: 100%
- Impurities (identity and concentrations): Information not available
- Composition of test material, percentage of components: Information not available
- Isomers composition: Information not available
- Purity test date: Information not available
- Lot/batch No.: Information not available
- Expiration date of the lot/batch: Information not available
- Stability under test conditions: Stable under normal temperature and pressure
- Storage condition of test material: Room temperature, in the dark
Constituent 1
Results and discussion
Vapour pressure
- Temp.:
- 25 °C
- Vapour pressure:
- 0.54 Pa
Transition / decomposition
- Transition / decomposition:
- no
Any other information on results incl. tables
Calculation
1) The vapour pressure is related to the observed mass difference by the following equation:
Vp = ρm ∙g / A
where:
Vp = vapour pressure (Pa)
ρm =mass difference (kg)g = acceleration due to gravity (9.813ms-2)
A = area of the orifice (7.06858x10-6m2)
2) The vapour pressure is related to temperature by the following equation:
Log10[Vp (Pa)] = [slope / temperature (K)]+ intercept
A plot ofLog10[Vp (Pa)] versus reciprocal temperature [1/T(K)] therefore gives a straight line graph.
The vapour pressure of the sample was measured over a range of temperatures to enable extrapolation to 298.15 K.
Results
Run 1:
| Temperature (°C) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
| 8 | 281.15 | 0.003556820 | 112.82 | 1,13E-04 | 0.156623064 | -0.805144283 |
| 9 | 282.15 | 0.003544214 | 120.63 | 1,21E-04 | 0.167465345 | -0.776075051 |
| 10 | 283.15 | 0.003531697 | 129.40 | 1,29E-04 | 0.179640352 | -0.745596102 |
| 11 | 284.15 | 0.003519268 | 142.34 | 1,42E-04 | 0.197604387 | -0.704203417 |
| 12 | 285.15 | 0.003506926 | 145.44 | 1,45E-04 | 0.201907982 | -0.694846513 |
| 13 | 286.15 | 0.003494671 | 165.01 | 1,65E-04 | 0.229076155 | -0.640020114 |
| 14 | 287.15 | 0.003482500 | 184.26 | 1,84E-04 | 0.255800087 | -0.592099312 |
| 15 | 288.15 | 0.003470415 | 193.88 | 1,94E-04 | 0.269155112 | -0.569997368 |
A plot of Log10[vapour pressure (Pa)] versus reciprocal temperature [1/T(K)] for Run 1 gives the following statistical data using an unweighted least squares treatment:
Slope -2788.061; Standard deviation in slope 136.534; Intercept 9.104; Standard deviation in intercept 0.480.
The results obtained indicate the following vapour pressure relationship: Log10(Vp (Pa)) = -2788.061/temp(K) + 9.104.
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.247.
Run 2:
| Temperature (°C) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
| 7 | 280.15 | 0.003569516 | 99.35 | 9,94E-05 | 0.137923253 | -0.860362507 |
| 8 | 281.15 | 0.003556820 | 106.19 | 1,06E-04 | 0.147418926 | -0.831446758 |
| 9 | 282.15 | 0.003544214 | 115.50 | 1,16E-04 | 0.160343591 | -0.794948395 |
| 10 | 283.15 | 0.003531697 | 123.41 | 1,23E-04 | 0.171324697 | -0.766180026 |
| 11 | 284.15 | 0.003519268 | 137.74 | 1,38E-04 | 0.191218409 | -0.718470300 |
| 12 | 285.15 | 0.003506926 | 147.47 | 1,48E-04 | 0.204726142 | -0.688826698 |
| 13 | 286.15 | 0.003494671 | 158.70 | 1,59E-04 | 0.220316259 | -0.656953452 |
| 14 | 287.15 | 0.003482500 | 172.28 | 1,72E-04 | 0.239168778 | -0.621295516 |
| 15 | 288.15 | 0.003470415 | 190.57 | 1,91E-04 | 0.264559984 | -0.577475845 |
A plot of Log10 [vapour pressure (Pa)] versus reciprocal temperature [1/T(K)] for Run 2 gives the following statistical data using an unweighted least squares treatment:
Slope -2845.534; Standard deviation in slope 53.393; Intercept 9.291; Standard deviation in intercept 0.188.
The results obtained indicate the following vapour pressure relationship: Log10(Vp (Pa)) = -2845.534/temp(K) + 9.291.
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.247.
Run 3:
| Temperature (°C) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
| 7 | 280.15 | 0.003569516 | 89.30 | 8,93E-05 | 0.123971279 | -0.906678920 |
| 8 | 281.15 | 0.003556820 | 95.82 | 9,58E-05 | 0.133022709 | -0.876074212 |
| 9 | 282.15 | 0.003544214 | 105.02 | 1,05E-04 | 0.145794666 | -0.836258365 |
| 10 | 283.15 | 0.003531697 | 123.52 | 1,24E-04 | 0.171477406 | -0.765793096 |
| 11 | 284.15 | 0.003519268 | 119.67 | 1,20E-04 | 0.166132619 | -0.779545088 |
| 12 | 285.15 | 0.003506926 | 130.79 | 1,31E-04 | 0.181570028 | -0.740955839 |
| 14 | 287.15 | 0.003482500 | 163.19 | 1,63E-04 | 0.226549529 | -0.644836836 |
| 15 | 288.15 | 0.003470415 | 178.06 | 1,78E-04 | 0.247192899 | -0.606964010 |
A plot of Log10[vapour pressure (Pa)] versus reciprocal temperature [1/T(K)] for Run 3 gives the following statistical data using an unweighted least squares treatment:
Slope -2983.149; Standard deviation in slope 187.129; Intercept 9.739; Standard deviation in intercept 0.659.
The results obtained indicate the following vapour pressure relationship: Log10(Vp (Pa)) = -2983.149/temp(K) + 9.739
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.267.
Run 4:
| Temperature (°C) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
| 8 | 281.15 | 0.003556820 | 88.55 | 8,86E-05 | 0.122930086 | -0.910341813 |
| 9 | 282.15 | 0.003544214 | 98.07 | 9,81E-05 | 0.136146285 | -0.865994203 |
| 10 | 283.15 | 0.003531697 | 107.48 | 1,08E-04 | 0.149209776 | -0.826202721 |
| 11 | 284.15 | 0.003519268 | 115.71 | 1,16E-04 | 0.160635125 | -0.794159485 |
| 12 | 285.15 | 0.003506926 | 130.36 | 1,30E-04 | 0.180973078 | -0.742386027 |
| 13 | 286.15 | 0.003494671 | 140.84 | 1,41E-04 | 0.195522003 | -0.708804362 |
| 14 | 287.15 | 0.003482500 | 163.62 | 1,64E-04 | 0.227146479 | -0.643693990 |
| 15 | 288.15 | 0.003470415 | 168.86 | 1,69E-04 | 0.234420942 | -0.630003594 |
A plot of Log10[vapour pressure (Pa)] versus reciprocal temperature [1/T(K)] for Run 4 gives the following statistical data using an unweighted least squares treatment:
Slope -3290.187; Standard deviation in slope 98.126; Intercept 10.795; Standard deviation in intercept 0.345.
The results obtained indicate the following vapour pressure relationship: Log10(Vp (Pa)) = -3290.187/temp(K) + 10.795
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.240.
Run 5:
| Temperature (°C) | Temperature (K) | Reciprocal Temperature (K-1) | Mass Difference (µg) | Mass Difference (kg) | Vapour Pressure (Pa) | Log10Vp |
| 6 | 279.15 | 0.003582303 | 76.78 | 7,68E-05 | 0.106590311 | -0.972282271 |
| 7 | 280.15 | 0.003569516 | 85.87 | 8,59E-05 | 0.119209560 | -0.923688916 |
| 8 | 281.15 | 0.003556820 | 91.54 | 9,15E-05 | 0.127080972 | -0.895919471 |
| 9 | 282.15 | 0.003544214 | 100.31 | 1,00E-04 | 0.139255979 | -0.856186148 |
| 10 | 283.15 | 0.003531697 | 105.23 | 1,05E-04 | 0.146086200 | -0.835390808 |
| 11 | 284.15 | 0.003519268 | 114.53 | 1,15E-04 | 0.158996982 | -0.798611118 |
| 12 | 285.15 | 0.003506926 | 121.27 | 1,21E-04 | 0.168353829 | -0.773777001 |
| 13 | 286.15 | 0.003494671 | 134.64 | 1,35E-04 | 0.186914815 | -0.728356276 |
| 14 | 287.15 | 0.003482500 | 145.65 | 1,46E-04 | 0.202199515 | -0.694219890 |
| 15 | 288.15 | 0.003470415 | 155.60 | 1,56E-04 | 0.216012664 | -0.665520786 |
A plot of Log10[vapour pressure (Pa)] versus reciprocal temperature [1/T(K)] for Run 5 gives the following statistical data using an unweighted least squares treatment:
Slope -2675.919; Standard deviation in slope 55.686; Intercept 8.620; Standard deviation in intercept 0.196.
The results obtained indicate the following vapour pressure relationship: Log10(Vp (Pa)) = -2675.919/temp(K) + 8.620
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.355.
Summary of results
| Run | Log10[Vp(25°C)] |
| 1 | -0.247 |
| 2 | -0.253 |
| 3 | -0.267 |
| 4 | -0.240 |
| 5 | -0.355 |
| Mean -0.272 Vapour Pressure 5.4 x 10-1 Pa |
|
The test material did not change in appearance under the conditions used in the determination.
Applicant's summary and conclusion
- Conclusions:
- vapour pressure = 0,54 Pa (at 25°C)
- Executive summary:
According to EU Method A.4 the vapour pressure was determined using a vapour pressure balance with measurements being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25 °C.
The vapour pressure of the test material has been determined to be 5.4 x 10-1 Pa at 25 ºC (arithmetic mean of five determinations) - the test material did not change in appearance under the conditions used in the determination.
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