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EC number: 255-615-9 | CAS number: 41999-70-6
Vapour pressure
Administrative data
Link to relevant study record(s)
- Endpoint:
- vapour pressure
- Type of information:
- experimental study
- Adequacy of study:
- key study
- Study period:
- 2018-02-15 - 2018-02-18
- Reliability:
- 1 (reliable without restriction)
- Rationale for reliability incl. deficiencies:
- guideline study
- Qualifier:
- according to guideline
- Guideline:
- OECD Guideline 104 (Vapour Pressure Curve)
- Version / remarks:
- 23 March 2006
- Deviations:
- no
- Qualifier:
- according to guideline
- Guideline:
- EU Method A.4 (Vapour Pressure)
- Version / remarks:
- EC No. 440/2008 of 30 May 2008
- Deviations:
- no
- GLP compliance:
- yes (incl. QA statement)
- Type of method:
- effusion method: vapour pressure balance
- Specific details on test material used for the study:
- Information as provided by the Sponsor:
Appearance/Physical state: Clear colorless liquid
Batch: PFW110370
Purity: 99.10%
Expiry: 31 December 2018
Storage conditions: Room temperature in the dark - Key result
- Temp.:
- 25 °C
- Vapour pressure:
- 2 Pa
- Conclusions:
- The vapor pressure of the test item has been determined to be 2.0 Pa at 25 ºC.
- Executive summary:
The vapor pressure of the test substance has been determined to be 2.0 Pa at 25 °C using the vapor pressure balance method according to Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.
Reference
Recorded temperatures, mass differences and the resulting calculated values of vapor pressure are shown in the following tables:
Run 1
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
0 |
273.15 |
0.0036610 |
132.92 |
1.3292e-07 |
0.1845270 |
-0.7339400 |
1 |
274.15 |
0.0036476 |
143.52 |
1.4352e-07 |
0.1992425 |
-0.7006180 |
2 |
275.15 |
0.0036344 |
157.68 |
1.5768e-07 |
0.2189002 |
-0.6597538 |
3 |
276.15 |
0.0036212 |
166.35 |
1.6635e-07 |
0.2309364 |
-0.6365076 |
4 |
277.15 |
0.0036082 |
185.70 |
1.8570e-07 |
0.2577992 |
-0.5887185 |
5 |
278.15 |
0.0035952 |
222.16 |
2.2216e-07 |
0.3084150 |
-0.5108645 |
6 |
279.15 |
0.0035823 |
236.68 |
2.3668e-07 |
0.3285725 |
-0.4833688 |
7 |
280.15 |
0.0035695 |
255.56 |
2.5556e-07 |
0.3547828 |
-0.4500375 |
8 |
281.15 |
0.0035568 |
271.72 |
2.7172e-07 |
0.3772170 |
-0.4234088 |
9 |
282.15 |
0.0035442 |
308.95 |
3.0895e-07 |
0.4289018 |
-0.3676422 |
10 |
283.15 |
0.0035317 |
340.88 |
3.4088e-07 |
0.4732288 |
-0.3249289 |
A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-3.21 x 103 |
Standard error in slope: |
94.2 |
Intercept: |
11.0 |
Standard error in intercept: |
0.339 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -3.21 x 103/temp(K) + 11.0
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.241.
Run 2
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
0 |
273.15 |
0.0036610 |
126.42 |
1.2642e-07 |
0.1755033 |
-0.7557146 |
1 |
274.15 |
0.0036476 |
127.27 |
1.2727e-07 |
0.1766834 |
-0.7528043 |
2 |
275.15 |
0.0036344 |
145.30 |
1.4530e-07 |
0.2017136 |
-0.6952648 |
3 |
276.15 |
0.0036212 |
158.42 |
1.5842e-07 |
0.2199275 |
-0.6577204 |
4 |
277.15 |
0.0036082 |
193.18 |
1.9318e-07 |
0.2681833 |
-0.5715682 |
5 |
278.15 |
0.0035952 |
201.23 |
2.0123e-07 |
0.2793588 |
-0.5538377 |
6 |
279.15 |
0.0035823 |
227.19 |
2.2719e-07 |
0.3153979 |
-0.5011412 |
7 |
280.15 |
0.0035695 |
240.40 |
2.4040e-07 |
0.3337368 |
-0.4765959 |
8 |
281.15 |
0.0035568 |
322.86 |
3.2286e-07 |
0.4482124 |
-0.3485161 |
9 |
282.15 |
0.0035442 |
302.10 |
3.0210e-07 |
0.4193922 |
-0.3773797 |
10 |
283.15 |
0.0035317 |
348.11 |
3.4811e-07 |
0.4832659 |
-0.3158139 |
A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-3.64 x 103 |
Standard error in slope: |
193 |
Intercept: |
12.5 |
Standard error in intercept: |
0.695 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -3.64 x 103/temp(K) + 12.5
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.333.
Run 3
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
0 |
273.15 |
0.0036610 |
122.26 |
1.2226e-07 |
0.1697282 |
-0.7702460 |
1 |
274.15 |
0.0036476 |
128.52 |
12852e-07 |
0.1784187 |
-0.7485597 |
2 |
275.15 |
0.0036344 |
140.23 |
1.4023e-07 |
0.1946752 |
-0.7106894 |
3 |
276.15 |
0.0036212 |
158.45 |
1.5845e-07 |
0.2199692 |
-0.6576381 |
4 |
277.15 |
0.0036082 |
172.31 |
1.7231e-07 |
0.2392104 |
-0.6212199 |
5 |
278.15 |
0.0035952 |
188.57 |
1.8857e-07 |
0.2617835 |
-0.5820578 |
6 |
279.15 |
0.0035823 |
219.66 |
2.1966e-07 |
0.3049444 |
-0.5157794 |
7 |
280.15 |
0.0035695 |
228.52 |
2.2852e-07 |
0.3172443 |
-0.4986062 |
8 |
281.15 |
0.0035568 |
268.29 |
2.6829e-07 |
0.3724553 |
-0.4289259 |
9 |
282.15 |
0.0035442 |
295.76 |
2.9576e-07 |
0.4105907 |
-0.3865909 |
10 |
283.15 |
0.0035317 |
329.84 |
3.2984e-07 |
0.4579024 |
-0.3392271 |
A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-3.42 x 103 |
Standard error in slope: |
95.9 |
Intercept: |
11.7 |
Standard error in intercept: |
0.345 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -3.42 x 103/temp(K) + 11.7
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.258.
Run 4
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
0 |
273.15 |
0.0036610 |
123.26 |
1.2326e-07 |
0.1711165 |
-0.7667082 |
1 |
274.15 |
0.0036476 |
126.77 |
1.2677e-07 |
0.1759892 |
-0.7545139 |
2 |
275.15 |
0.0036344 |
140.84 |
1.4084e-07 |
0.1955221 |
-0.7088044 |
3 |
276.15 |
0.0036212 |
159.13 |
1.5913e-07 |
0.2209132 |
-0.6557783 |
4 |
277.15 |
0.0036082 |
174.96 |
1.7496e-07 |
0.2428893 |
-0.6145916 |
5 |
278.15 |
0.0035952 |
216.36 |
2.1636e-07 |
0.3003631 |
-0.5223534 |
6 |
279.15 |
0.0035823 |
232.24 |
2.3224e-07 |
0.3224086 |
-0.4915934 |
7 |
280.15 |
0.0035695 |
264.65 |
2.6465e-07 |
0.3674020 |
-0.4348585 |
8 |
281.15 |
0.0035568 |
273.90 |
2.7390e-07 |
0.3802434 |
-0.4199383 |
9 |
282.15 |
0.0035442 |
315.40 |
3.1540e-07 |
0.4378560 |
-0.3586687 |
10 |
283.15 |
0.0035317 |
356.40 |
3.5640e-07 |
0.4947745 |
-0.3055927 |
A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-3.74 x 103 |
Standard error in slope: |
129 |
Intercept: |
12.9 |
Standard error in intercept: |
0.465 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -3.74 x 103/temp(K) + 12.9
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.355.
Run 5
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
0 |
273.15 |
0.0036610 |
119.25 |
1.1925e-07 |
0.1655496 |
-0.7810720 |
1 |
274.15 |
0.0036476 |
129.05 |
1.2905e-07 |
0.1791545 |
-0.7467724 |
2 |
275.15 |
0.0036344 |
137.16 |
1.3716e-07 |
0.1904132 |
-0.7203029 |
3 |
276.15 |
0.0036212 |
162.75 |
1.6275e-07 |
0.2259387 |
-0.6460094 |
4 |
277.15 |
0.0036082 |
172.78 |
1.7278e-07 |
0.2398629 |
-0.6200369 |
5 |
278.15 |
0.0035952 |
185.08 |
1.8508e-07 |
0.2569385 |
-0.5901709 |
6 |
279.15 |
0.0035823 |
215.34 |
2.1534e-07 |
0.2989471 |
-0.5244057 |
7 |
280.15 |
0.0035695 |
233.40 |
2.3340e-07 |
0.3240190 |
-0.4894295 |
8 |
281.15 |
0.0035568 |
272.15 |
2.7215e-07 |
0.3778139 |
-0.4227220 |
9 |
282.15 |
0.0035442 |
355.41 |
3.5541e-07 |
0.4934001 |
-0.3068007 |
10 |
283.15 |
0.0035317 |
356.31 |
3.5631e-07 |
0.4946496 |
-0.3057024 |
A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-3.82 x 103 |
Standard error in slope: |
20 |
Intercept: |
13.2 |
Standard error in intercept: |
0.737 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -3.82 x 103/temp(K) + 13.2
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.364.
Run 6
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
0 |
273.15 |
0.0036610 |
130.52 |
1.3052e-07 |
0.1811952 |
-0.7418533 |
1 |
274.15 |
0.0036476 |
130.37 |
1.3037e-07 |
0.1809870 |
-0.7423527 |
2 |
275.15 |
0.0036344 |
143.31 |
1.4331e-07 |
0.1989510 |
-0.7012539 |
3 |
276.15 |
0.0036212 |
155.82 |
1.5582e-07 |
0.2163181 |
-0.6649072 |
4 |
277.15 |
0.0036082 |
168.21 |
1.6821e-07 |
0.2335186 |
-0.6316786 |
5 |
278.15 |
0.0035952 |
182.79 |
1.8279e-07 |
0.2537594 |
-0.5955779 |
6 |
279.15 |
0.0035823 |
251.61 |
2.5162e-07 |
0.3492991 |
-0.4568025 |
7 |
280.15 |
0.0035695 |
232.70 |
2.3270e-07 |
0.3230472 |
-0.4907340 |
8 |
281.15 |
0.0035568 |
270.23 |
2.7023e-07 |
0.3751485 |
-0.4257968 |
9 |
282.15 |
0.0035442 |
295.43 |
2.9543e-07 |
0.4101325 |
-0.3870758 |
10 |
283.15 |
0.0035317 |
337.55 |
3.3755e-07 |
0.4686059 |
-0.3291923 |
A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-3.40 x 103 |
Standard error in slope: |
223 |
Intercept: |
11.7 |
Standard error in intercept: |
0.801 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -3.40 x 103/temp(K) + 11.7
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.260.
Run 7
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapor Pressure (Pa) |
Log10Vp |
0 |
273.15 |
0.0036610 |
117.37 |
1.1737e-07 |
0.1629396 |
-0.7879733 |
1 |
274.15 |
0.0036476 |
126.01 |
1.2601e-07 |
0.1749342 |
-0.7571254 |
2 |
275.15 |
0.0036344 |
131.65 |
1.3165e-07 |
0.1827639 |
-0.7381095 |
3 |
276.15 |
0.0036212 |
147.85 |
1.4785e-07 |
0.2052537 |
-0.6877091 |
4 |
277.15 |
0.0036082 |
159.87 |
1.5987e-07 |
0.2219405 |
-0.6537634 |
5 |
278.15 |
0.0035952 |
182.44 |
1.8244e-07 |
0.2532735 |
-0.5964103 |
6 |
279.15 |
0.0035823 |
200.76 |
2.0076e-07 |
0.2787063 |
-0.5548532 |
7 |
280.15 |
0.0035695 |
224.26 |
2.2426e-07 |
0.3113303 |
-0.5067786 |
8 |
281.15 |
0.0035568 |
247.37 |
2.4737e-07 |
0.3434129 |
-0.4641833 |
9 |
282.15 |
0.0035442 |
290.24 |
2.9024e-07 |
0.4029275 |
-0.3947731 |
10 |
283.15 |
0.0035317 |
394.63 |
3.9463e-07 |
0.5478475 |
-0.2613403 |
A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.
Slope: |
-3.77 x 103 |
Standard error in slope: |
262 |
Intercept: |
13.0 |
Standard error in intercept: |
0.943 |
The results obtained indicate the following vapor pressure relationship:
Log10(Vp (Pa)) = -3.77 x 103/temp(K) + 13.0
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 0.328.
The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table.
Summary of Vapor Pressure Data
Run |
Log10[Vp(25 ºC)] |
1 |
0.241 |
2 |
0.333 |
3 |
0.258 |
4 |
0.355 |
5 |
0.364 |
6 |
0.260 |
7 |
0.328 |
Mean |
0.306 |
Vapor Pressure |
2.02 Pa |
The test item did not change in appearance under the conditions used in the determination
A total of 7 runs were completed for the main sequence. All 7 runs were used as equilibrium had been reached.
The results may represent rounded values obtained by calculations based on the exact raw data.
Description of key information
The vapor pressure of the test substance has been determined to be 2.0 Pa at 25 °C using the vapor pressure balance method according to EU Method A.4 and OECD Guideline 104 (K1, Envigo, 2018).
Key value for chemical safety assessment
- Vapour pressure:
- 2 Pa
- at the temperature of:
- 25 °C
Additional information
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Reproduction or further distribution of this information may be subject to copyright protection. Use of the information without obtaining the permission from the owner(s) of the respective information might violate the rights of the owner.
