Registration Dossier

Physical & Chemical properties

Vapour pressure

Currently viewing:

Administrative data

Link to relevant study record(s)

Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
June 2015
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study
Remarks:
Study conducted according to OECD 104 and EU A.4 guidelines, under GLP without deviation and with certificate of analysis included.
Reason / purpose:
reference to other study
Reason / purpose:
reference to same study
Qualifier:
according to
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Deviations:
no
Qualifier:
according to
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. certificate)
Remarks:
2015-03-05
Type of method:
dynamic method
Remarks:
Knudsen Effusion Method
Test no.:
#1
Temp.:
293.15 K
Vapour pressure:
ca. 2.39 Pa
Remarks on result:
other: First trial
Test no.:
#1
Temp.:
298.15 K
Vapour pressure:
ca. 4.75 Pa
Remarks on result:
other: First trial
Test no.:
#2
Temp.:
293.15 K
Vapour pressure:
ca. 2.38 Pa
Remarks on result:
other: Second trial
Test no.:
#2
Temp.:
298.15 K
Vapour pressure:
ca. 4.53 Pa
Remarks on result:
other: Second trial
Key result
Temp.:
293.15 K
Vapour pressure:
ca. 2.39 Pa
Remarks on result:
other: Mean
Key result
Temp.:
298.15 K
Vapour pressure:
ca. 4.64 Pa
Remarks on result:
other: Mean

First trial:

Mass loss (mg)

Mass loss duration (s)

Vapour pressure (Pa)

Temperature (K)

1/T (K-1)

Log10(p)

0.360

600

3.56

296,35

3,374E-03

0,5516

0.762

600

7.61

301.70

3,315E-03

0,8811

1.786

600

18.01

307.90

3,248E-03

1,2555

4.160

600

42.42

314.85

3,176E-03

1,6275

9.121

600

94.14

322.6

3,100E-03

1,9738

A plot of Log10(p) versus reciprocal temperature (1/T) (with p in Pa and T in K) gives the following statistical data using an unweighted least square treatment.

Slope              -5213.1 

Intercept          18.162 

                   0.9982

 

The results obtained indicate the following vapour pressure relationship: 

Log10(p (Pa)) = -5213.1 / T (K) +18.162

 

The above equation yields a vapour pressure of 2.39 Pa at 293.15 K and 4.75 Pa at 298.15 K.

Second trial:

Mass loss (mg)

Mass loss duration (s)

Vapour pressure (Pa)

Temperature (K)

1/T (K-1)

Log10(p)

0.349

600

3.45

296,15

3,377E-03

0,5380

0.745

600

7.44

302.30

3,308E-03

0,8718

1.754

600

17.72

309.00

3,236E-03

1,2484

4.081

600

41.71

316.40

3,161E-03

1,6203

8.997

600

93.14

324.55

3,081E-03

1,9691

A plot of Log10(p) versus reciprocal temperature (1/T) (with p in Pa and T in K) gives the following statistical data using an unweighted least square treatment.

Slope              -4886.9

Intercept          17.047 

                   0.9991

 

The results obtained indicate the following vapour pressure relationship:

Log10(p (Pa)) = -4886.9/ T (K) +17.047

 

The above equation yields a vapour pressure of 2.38 Pa at 293.15 K and 4.53 Pa at 298.15 K.

Conclusions:
Using the Knudsen Effusion method according to guideline OECD 104 and method EU A.4, vapour pressure of NEROL is 2.39 Pa at 20°C and 4.64 Pa at 25°C were estimated for the test item.
Executive summary:

A study was performed to determine the vapour pressure of test item nerol. The method followed was designed to be compliant with the OECD Guideline for Testing of Chemicals No. 104, "Vapour Pressure", adopted in March, 2006 and Regulation (EC) No 761/2009, EC A4, 23 July 2009.

In this dynamic method, the mass of the test substance flowing out per unit of time of a Knudsen cell in the form of vapour, through a micro-orifice under ultra-vacuum conditions was determined at various specified temperatures (from 25 to 65°C). The Hertz-Knudsen equation was used to calculate the vapour pressure corresponding to the mass loss rate.

The Log10 (Vapour Pressure (Pa)) was plotted against 1/T (K) and a linear function was obtained. With this equation, the vapour pressure has been calculated for temperatures of 20°C and 25°C.

Two trials were conducted and five points were recorded for each trial.

Log (Vapour Pressure (Pa)) was plotted against reciprocal temperature and values of vapour pressure were calculated at 20°C and 25°C with the linear function parameters (slope and intercept).

These values respect validity criteria (less than 20% of difference) and the linear functions obtained own a correlation coefficient R² over 0.95.

Moreover the calculated values showed good correspondence with the experimentally determined ones.

In conclusion, the vapour pressure of nerol is 2.39 Pa at 20°C and 4.64 Pa at 25°C.

Description of key information

The vapour pressure of nerol was determined with the knudsen effusion method.
The vapour pressure of nerol was 2.39 Pa at 20°C and 4.64 Pa at 25°C.

Key value for chemical safety assessment

Vapour pressure:
2.39 Pa
at the temperature of:
20 °C

Additional information

Key study was performed in order to determine the vapour pressure of nerol according to EU method A.4 and OECD 104 using a dynamic method (knudsen effusion method).

No observations were made which might cause doubts concerning the validity of the study outcome.

Therefore, the study is considered as reliable without restriction and the calculated vapour pressures at 20 and 25°C can be used as key values for chemical safety assessment.