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EC number: - | CAS number: -
Vapour pressure
Administrative data
- Endpoint:
- vapour pressure
- Type of information:
- experimental study
- Adequacy of study:
- key study
- Study period:
- 15 January 2009 to 05 February 2009
- Reliability:
- 1 (reliable without restriction)
- Rationale for reliability incl. deficiencies:
- other: Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of relevant results.
Data source
Reference
- Reference Type:
- study report
- Title:
- Unnamed
- Year:
- 2 009
- Report date:
- 2009
Materials and methods
Test guideline
- Qualifier:
- according to guideline
- Guideline:
- EU Method A.4 (Vapour Pressure)
- Deviations:
- no
- GLP compliance:
- yes (incl. QA statement)
- Remarks:
- Date of inspection: 19 August 2008; Date of signature: 29 January 2009
- Type of method:
- effusion method: vapour pressure balance
Test material
Results and discussion
Vapour pressure
- Temp.:
- 25 °C
- Vapour pressure:
- 0 Pa
Any other information on results incl. tables
Please see attachment 2 below for graphs.
Run1
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
128 |
401.15 |
0.002492833 |
6.49 |
6.490E-09 |
0.009009783 |
-2.045285682 |
129 |
402.15 |
0.002486634 |
7.11 |
7.110E-09 |
0.009870502 |
-2.005660778 |
130 |
403.15 |
0.002480466 |
8.34 |
8.340E-09 |
0.011578057 |
-1.936364328 |
131 |
404.15 |
0.002474329 |
9.48 |
9.480E-09 |
0.013160669 |
-1.880722041 |
132 |
405.15 |
0.002468222 |
10.40 |
1.040E-08 |
0.014437864 |
-1.840497039 |
133 |
406.15 |
0.002462145 |
11.84 |
1.184E-08 |
0.016436953 |
-1.784178676 |
134 |
407.15 |
0.002456097 |
13.70 |
1.370E-08 |
0.019019110 |
-1.720809812 |
135 |
408.15 |
0.002450080 |
15.04 |
1.504E-08 |
0.020879373 |
-1.680282542 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.
Slope -8724.859
Standard deviation in slope 185.348
Intercept 19.700
Standard deviation in intercept 0.458
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -8724.859 /temp(K) + 19.700
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -9.563.
Run 2
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
128 |
401.15 |
0.002492833 |
6.39 |
6.390E-09 |
0.008870957 |
-2.052029521 |
129 |
402.15 |
0.002486634 |
6.90 |
6.900E-09 |
0.009578968 |
-2.018681288 |
130 |
403.15 |
0.002480466 |
7.93 |
7.930E-09 |
0.011008872 |
-1.958257191 |
131 |
404.15 |
0.002474329 |
9.68 |
9.680E-09 |
0.013438320 |
-1.871655021 |
132 |
405.15 |
0.002468222 |
11.64 |
1.164E-08 |
0.016159302 |
-1.791577398 |
133 |
406.15 |
0.002462145 |
11.43 |
1.143E-08 |
0.015867768 |
-1.799484148 |
134 |
407.15 |
0.002456097 |
12.57 |
1.257E-08 |
0.017450380 |
-1.758195101 |
135 |
408.15 |
0.002450080 |
15.14 |
1.514E-08 |
0.021018199 |
-1.677404504 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.
Slope -8737.351
Standard deviation in slope 653.118
Intercept 19.727
Standard deviation in intercept 1.614
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -8737.351 /temp(K) + 19.727
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -9.578.
Run 3
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
128 |
401.15 |
0.002492833 |
6.18 |
6.180E-09 |
0.008579423 |
-2.066541904 |
129 |
402.15 |
0.002486634 |
6.39 |
6.390E-09 |
0.008870957 |
-2.052029521 |
130 |
403.15 |
0.002480466 |
7.11 |
7.110E-09 |
0.009870502 |
-2.005660778 |
131 |
404.15 |
0.002474329 |
8.03 |
8.030E-09 |
0.011147697 |
-1.952814833 |
132 |
405.15 |
0.002468222 |
9.89 |
9.890E-09 |
0.013729854 |
-1.862334087 |
133 |
406.15 |
0.002462145 |
11.74 |
1.174E-08 |
0.016298128 |
-1.787862282 |
134 |
407.15 |
0.002456097 |
11.95 |
1.195E-08 |
0.016589662 |
-1.780162473 |
135 |
408.15 |
0.002450080 |
13.49 |
1.349E-08 |
0.018727576 |
-1.727518429 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.
Slope -8724.455
Standard deviation in slope 610.393
Intercept 19.657
Standard deviation in intercept 1.509
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -8724.455 /temp(K) + 19.657
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -9.605.
Run 4
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
128 |
401.15 |
0.002492833 |
5.36 |
5.360E-09 |
0.007441053 |
-2.128365589 |
129 |
402.15 |
0.002486634 |
6.08 |
6.080E-09 |
0.008440598 |
-2.073626799 |
130 |
403.15 |
0.002480466 |
6.39 |
6.390E-09 |
0.008870957 |
-2.052029521 |
131 |
404.15 |
0.002474329 |
7.93 |
7.930E-09 |
0.011008872 |
-1.958257191 |
132 |
405.15 |
0.002468222 |
8.45 |
8.450E-09 |
0.011730765 |
-1.930673670 |
133 |
406.15 |
0.002462145 |
9.06 |
9.060E-09 |
0.012577601 |
-1.900402181 |
134 |
407.15 |
0.002456097 |
11.43 |
1.143E-08 |
0.015867768 |
-1.799484148 |
135 |
408.15 |
0.002450080 |
11.84 |
1.184E-08 |
0.016436953 |
-1.784178676 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.
Slope -8307.816
Standard deviation in slope 498.441
Intercept 18.578
Standard deviation in intercept 1.232
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -8307.816 /temp(K) + 18.578
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -9.286.
Run 5
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
128 |
401.15 |
0.002492833 |
5.36 |
5.360E-09 |
0.007441053 |
-2.128365589 |
129 |
402.15 |
0.002486634 |
5.97 |
5.970E-09 |
0.008287890 |
-2.081556048 |
130 |
403.15 |
0.002480466 |
6.08 |
6.080E-09 |
0.008440598 |
-2.073626799 |
131 |
404.15 |
0.002474329 |
7.00 |
7.000E-09 |
0.009717793 |
-2.012432339 |
132 |
405.15 |
0.002468222 |
8.65 |
8.650E-09 |
0.012008416 |
-1.920514271 |
133 |
406.15 |
0.002462145 |
9.17 |
9.170E-09 |
0.012730309 |
-1.895161043 |
134 |
407.15 |
0.002456097 |
10.61 |
1.061E-08 |
0.014729398 |
-1.831814995 |
135 |
408.15 |
0.002450080 |
12.26 |
1.226E-08 |
0.017020021 |
-1.769039909 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.
Slope -8555.661
Standard deviation in slope 528.799
Intercept 19.180
Standard deviation in intercept 1.307
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -8555.661 /temp(K) + 19.180
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -9.516.
Summary of Results
Run |
Log10[Vp(25ºC)] |
1 |
-9.563 |
2 |
-9.578 |
3 |
-9.605 |
4 |
-9.286 |
5 |
-9.516 |
Mean |
-9.510 |
Vapour Pressure |
3.1 x 10-10Pa |
Applicant's summary and conclusion
- Conclusions:
- The vapour pressure of the test material has been determined to be 3.1 x 10-10 Pa at 25ºC.
- Executive summary:
The vapour pressure was determined using a vapour pressure balance system withasurents being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using Method A4 Vapour Pressure of Council Regulation (EC) No 440/2208 of 30 May 2008.
The vapour pressure of the test material has been determined to be 3.1 x 10-10 Pa at 25ºC.
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