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Physical & Chemical properties

Vapour pressure

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Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
30 July to 06 August 2018
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study
Remarks:
GLP study in accordance with international guidelines.
Qualifier:
according to
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Deviations:
no
Qualifier:
according to
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. certificate)
Remarks:
Date of Inspection: 18 July 2017 - 20 July 2017 Date on Certificate: 28 November 2017
Type of method:
effusion method: vapour pressure balance
Key result
Test no.:
#1
Temp.:
25 °C
Vapour pressure:
0 Pa

Recorded temperatures, mass differences and the resulting calculated values of vapour pressure are shown in the following tables:

Run 5

Table 1 - Vapour Pressure Data

 

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass difference (kg)

Vapour pressure (Pa)

Log10Vp

100

373.15

0.002680

56.66

5.666e-08

0.07866

-1.10425

101

374.15

0.002673

66.01

6.601e-08

0.09164

-1.03791

102

375.15

0.002666

76.08

7.608e-08

0.10562

-0.97625

103

376.15

0.002659

81.39

8.139e-08

0.11299

-0.94696

104

377.15

0.002651

85.16

8.516e-08

0.11822

-0.92731

105

378.15

0.002644

93.49

9.349e-08

0.12979

-0.88676

106

379.15

0.002637

114.01

1.140e-07

0.15828

-0.80057

107

380.15

0.002631

118.35

1.183e-07

0.16430

-0.78436

108

381.15

0.002624

124.24

1.242e-07

0.17248

-0.76326

109

382.15

0.002617

142.78

1.428e-07

0.19822

-0.70285

110

383.15

0.002610

160.96

1.610e-07

0.22345

-0.65082

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

 

Slope: -6.10 x 103

Standard error in slope: 240

Intercept: 15.3

Standard error in intercept: 0.634

 

The results obtained indicate the following vapour pressure relationship:

 

Log10(Vp(Pa)) = -6.10 x 103/temp (K) + 1.53

 

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -5.20.

 

Run 6

Table 2 - Vapour Pressure Data

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass difference (kg)

Vapour pressure (Pa)

Log10Vp

100

373.15

0.002680

52.73

5.273e-08

0.07320

-1.13549

101

374.15

0.002673

65.23

6.523e-08

0.09056

-1.04306

102

375.15

0.002666

70.39

7.039e-08

0.09772

-1.01002

103

376.15

0.002659

72.56

7.256e-08

0.10073

-0.99684

104

377.15

0.002651

84.72

8.472e-08

0.11761

-0.92956

105

378.15

0.002644

98.11

9.811e-08

0.13620

-0.86582

106

379.15

0.002637

101.55

1.016e-07

0.14098

-0.85084

107

380.15

0.002631

119.67

1.197e-07

0.16613

-0.77955

108

381.15

0.002624

124.65

1.247e-07

0.17305

-0.76183

109

382.15

0.002617

141.70

1.417e-07

0.19672

-0.70615

110

383.15

0.002610

157.59

1.576e-07

0.21878

-0.65999

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

 

Slope: -6.47 x 103

Standard error in slope: 228

Intercept: 16.2

Standard error in intercept: 0.603

 

The results obtained indicate the following vapour pressure relationship:

 

Log10(Vp(Pa)) = -6.47 x 103/temp (K) + 16.2

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -5.47

Run 7

Table 3 - Vapour Pressure Data

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass difference (kg)

Vapour pressure (Pa)

Log10Vp

100

373.15

0.002680

49.68

4.968e-08

0.06922

-1.15977

101

374.15

0.002673

58.66

5.866e-08

0.08144

-1.08916

102

375.15

0.002666

62.61

6.261e-08

0.08692

-1.06088

103

376.15

0.002659

71.95

7.195e-08

0.09989

-1.00048

104

377.15

0.002651

82.10

8.210e-08

0.11398

-0.94317

105

378.15

0.002644

90.80

9.080e-08

0.12605

-0.89946

106

379.15

0.002637

100.55

1.005e-07

0.13959

-0.85515

107

380.15

0.002631

100.66

1.007e-07

0.13974

-0.85468

108

381.15

0.002624

118.41

1.184e-07

0.16438

-0.78415

109

382.15

0.002617

130.95

1.309e-07

0.18179

-0.74043

110

383.15

0.002610

145.17

1.452e-07

0.20153

-0.69566

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

 

Slope: -6.40 x 103

Standard error in slope: 185

Intercept: 16.0

Standard error in intercept: 0.489

 

The results obtained indicate the following vapour pressure relationship:

 

Log10(Vp(Pa)) = -6.40 x 103/temp (K) + 16.0

 

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -5.46

Run 8

Table 4 - Vapour Pressure Data

 

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass difference (kg)

Vapour pressure (Pa)

Log10Vp

100

373.15

0.002680

47.14

4.714e-08

0.06544

-1.18416

101

374.15

0.002673

54.78

5.478e-08

0.07605

-1.11890

102

375.15

0.002666

64.81

6.481e-08

0.08997

-1.04590

103

376.15

0.002659

70.56

7.056e-08

0.09796

-1.00895

104

377.15

0.002651

78.20

7.820e-08

0.10856

-0.96433

105

378.15

0.002644

80.97

8.097-08

0.11241

-0.94920

106

379.15

0.002637

93.56

9.356e-08

0.12989

-0.88642

107

380.15

0.002631

105.69

1.057e-07

0.14672

-0.83351

108

381.15

0.002624

115.66

1.157e-07

0.16057

-0.79434

109

382.15

0.002617

115.86

1.159e-07

0.16084

-0.79361

110

383.15

0.002610

131.82

1.318e-07

0.18300

-0.73755

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.

 

Slope: -6.13 x 103

Standard error in slope: 274

Intercept: 15.3

Standard error in intercept: 0.725

 

The results obtained indicate the following vapour pressure relationship:

 

Log10(Vp(Pa)) = -6.13 x 103/temp (K) + 15.3

 

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -5.28

Run 9

Table 5 - Vapour Pressure Data

 

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass difference (kg)

Vapour pressure (Pa)

Log10Vp

100

373.15

0.002680

45.32

4.532e-08

0.06292

-1.20121

101

374.15

0.002673

54.58

5.458e-08

0.07577

-1.12050

102

375.15

0.002666

60.97

6.097e-08

0.08464

-1.07242

103

376.15

0.002659

66.75

6.675e-08

0.09267

-1.03306

104

377.15

0.002651

68.30

6.830e-08

0.09482

-1.02310

105

378.15

0.002644

78.79

7.879e-08

0.10938

-0.96106

106

379.15

0.002637

88.09

8.809e-08

0.12229

-0.91261

107

380.15

0.002631

101.21

1.012e-07

0.14051

-0.85229

108

381.15

0.002624

102.87

1.029e-07

0.14281

-0.84524

109

382.15

0.002617

118.94

1.189e-07

0.16512

-0.78220

110

383.15

0.002610

132.99

1.330e-07

0.18462

-0.73372

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 9 gives the following statistical data using an unweighted least squares treatment.

 

Slope: -6.28 x 103

Standard error in slope: 237

Intercept: 15.7

Standard error in intercept: 0.627

 

The results obtained indicate the following vapour pressure relationship:

 

Log10(Vp(Pa)) = -6.28 x 103/temp (K) + 15.7

 

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -5.42

Run 10

Table 6 - Vapour Pressure Data

 

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass difference (kg)

Vapour pressure (Pa)

Log10Vp

100

373.15

0.002680

43.82

4.382e-08

0.06083

-1.21588

101

374.15

0.002673

50.27

5.027e-08

0.06979

-1.15621

102

375.15

0.002666

56.63

5.663e-08

0.07862

-1.10447

103

376.15

0.002659

60.99

6.099e-08

0.08467

-1.07227

104

377.15

0.002651

68.84

6.884e-08

0.09557

-1.01968

105

378.15

0.002644

76.51

7.651e-08

0.10622

-0.97379

106

379.15

0.002637

82.52

8.252e-08

0.11456

-0.94097

107

380.15

0.002631

94.95

9.495e-07

0.13181

-0.88005

108

381.15

0.002624

104.36

1.044e-07

0.14488

-0.83899

109

382.15

0.002617

111.53

1.115-07

0.15483

-0.81014

110

383.15

0.002610

1248.84

1.268e-07

0.17609

-0.75427

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 10 gives the following statistical data using an unweighted least squares treatment.

 

Slope: -6.43 x 103

Standard error in slope: 115

Intercept: 16.0

Standard error in intercept: 0.304

 

The results obtained indicate the following vapour pressure relationship:

 

Log10(Vp(Pa)) = -6.43 x 103/temp (K) + 16.0

 

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -5.54

The vapour pressures at 25 °C, extrapolated from each graph, are summarised in the following table:

Table 7 - Summary of Vapour Pressure Data

Run

Log10[Vp(25°C)]

5

-5.20

6

-5.47

7

-5.46

8

-5.28

9

-5.42

10

-5.54

 Mean

-5.39

Vapour Pressure

4.03 x 10-6Pa

The test item did not change in appearance under the conditions used in the determination.

A total of 10 runs were completed for the main sequence. Equilibrium with regard to vapour pressure has been reached over the final 6 runs. The final 6 runs have been used to determine vapour pressure.

The results may represent rounded values obtained by calculations based on exact raw data.

Conclusions:
The vapour pressure of the test item has been determined to be 4.0E-06 Pa at 25 °C.
Executive summary:

The vapour pressure of the test item has been determined to be 4.0E-06 Pa at 25°C using a procedure designed to be compatible with Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Description of key information

The vapour pressure of the test item has been determined to be 4.0E-06 Pa at 25 °C.

Key value for chemical safety assessment

Vapour pressure:
0 Pa
at the temperature of:
25 °C

Additional information

The vapour pressure of the test item has been determined to be 4.0E-06 Pa at 25°C using a procedure designed to be compatible with Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.