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Physical & Chemical properties

Vapour pressure

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Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
8th July 2010 - 8th August 2010
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: This study was conducted in accordance with international guidelines in a GLP testing laboratory.
Qualifier:
equivalent or similar to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. QA statement)
Type of method:
effusion method: vapour pressure balance
Key result
Temp.:
25 °C
Vapour pressure:
13 Pa
Remarks on result:
other: The test item did not change in appearance under the conditions used in the determination.
Transition / decomposition:
no

Run 1

Temperature
(oC)
Temperature (K) Reciprocal Temperature (K-1) Mass Difference (µg) Mass Difference (kg) Vapour Pressure (Pa) Log10Vp
-19 254.15 0.003934684 133.41 1.334E-07 0.185207259 -0.732341995
-18 255.15 0.003919263 143.06 1.431E-07 0.198603932 -0.702012158
-17 256.15 0.003903963 158.77 1.588E-07 0.220413437 -0.656761934
-16 257.15 0.003888781 179.58 1.796E-07 0.249303048 -0.603272412
-15 258.15 0.003873717 198.26 1.983E-07 0.275235674 -0.560295277
-14 259.15 0.003858769 224.08 2.241E-07 0.311080449 -0.507127283
-13 260.15 0.003843936 255.44 2.554E-07 0.354616163 -0.450241473
-12 261.15 0.003829217 280.36 2.804E-07 0.389211508 -0.409814327
-11 262.15 0.003814610 317.01 3.170E-07 0.440091098 -0.356457417
-10 263.15 0.003800114 351.46 3.515E-07 0.487916524 -0.311654474

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistaical data using an unweighted least squares treatment.

Slope: -3222.445

Std. dev. in slope: 57.032

Intercept: 11.931

Std. dev. in intercept: 0.221

The results obtained indicate the following vapour pressure relationship:

Log10 (Vp (Pa))=-3222.445/temp(K) + 11.931

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of 1.123

Run 2

Temperature
(oC)
Temperature (K) Reciprocal Temperature (K-1) Mass Difference (µg) Mass Difference (kg) Vapour Pressure (Pa) Log10Vp
-19 254.15 0.003934684 125.95 1.260E-07 0.174850868 -0.757332207
-18 255.15 0.003919263 135.84 1.358E-07 0.188580722 -0.724502706
-17 256.15 0.003903963 150.67 1.507E-07 0.209168561 -0.679503590
-16 257.15 0.003888781 167.50 1.675E-07 0.232532913 -0.633515567
-15 258.15 0.003873717 191.64 1.916E-07 0.266045418 -0.575044217
-14 259.15 0.003858769 215.18 2.152E-07 0.298724969 -0.524728476
-13 260.15 0.003843936 239.60 2.396E-07 0.332626185 -0.478043565
-12 261.15 0.003829217 266.13 2.661E-07 0.369456622 -0.432436545
-11 262.15 0.003814610 301.56 3.016E-07 0.418642539 -0.378156644
-10 263.15 0.003800114 336.75 3.368E-07 0.467495275 -0.330222774

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistaical data using an unweighted least squares treatment.

Slope: -3250.177

Std. dev. in slope: 54.313

Intercept: 12.016

Std. dev. in intercept: 0.210

The results obtained indicate the following vapour pressure relationship:

Log10 (Vp (Pa))=-3250.177/temp(K) + 12.016

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of 1.115

Run 3

Temperature
(oC)
Temperature (K) Reciprocal Temperature (K-1) Mass Difference (µg) Mass Difference (kg) Vapour Pressure (Pa) Log10Vp
-19 254.15 0.003934684 122.63 1.226E-07 0.170241858 -0.768933650
-18 255.15 0.003919263 134.63 1.346E-07 0.186900932 -0.728388533
-17 256.15 0.003903963 147.16 1.472E-07 0.204295782 -0.689740600
-16 257.15 0.003888781 159.00 1.590E-07 0.220732736 -0.656133254
-15 258.15 0.003873717 181.81 1.818E-07 0.252398859 -0.597912612
-14 259.15 0.003858769 211.38 2.114E-07 0.293449595 -0.532466485
-13 260.15 0.003843936 230.80 2.308E-07 0.320409531 -0.494294574
-12 261.15 0.003829217 262.49 2.625E-07 0.364403370 -0.438417616
-11 262.15 0.003814610 298.12 2.981E-07 0.413866938 -0.383139266
-10 263.15 0.003800114 330.70 3.307E-07 0.459096325 -0.338096184

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistaical data using an unweighted least squares treatment.

Slope: -3282.406

Std. dev. in slope: 86.818

Intercept: 12.129

Std. dev. in intercept: 0.336

The results obtained indicate the following vapour pressure relationship:

Log10 (Vp (Pa))=-3282.406/temp(K) + 12.129

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of 1.120

Run 4

Temperature
(oC)
Temperature (K) Reciprocal Temperature (K-1) Mass Difference (µg) Mass Difference (kg) Vapour Pressure (Pa) Log10Vp
-19 254.15 0.003934684 117.94 1.179E-07 0.163730936 -0.785869255
-18 255.15 0.003919263 134.08 1.341E-07 0.186137391 -0.730166377
-17 256.15 0.003903963 146.13 1.461E-07 0.202865878 -0.692790994
-16 257.15 0.003888781 162.52 1.625E-07 0.225619397 -0.646623565
-15 258.15 0.003873717 177.00 1.770E-07 0.245721347 -0.609557112
-14 259.15 0.003858769 200.33 2.003E-07 0.278109364 -0.555784388
-13 260.15 0.003843936 229.96 2.300E-07 0.319243395 -0.495878079
-12 261.15 0.003829217 256.88 2.569E-07 0.356615252 -0.447800086
-11 262.15 0.003814610 287.72 2.877E-07 0.399429073 -0.398560327
-10 263.15 0.003800114 325.33 3.253E-07 0.451641389 -0.345206266

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistaical data using an unweighted least squares treatment.

Slope: -3248.810

Std. dev. in slope: 66.317

Intercept: 11.991

Std. dev. in intercept: 0.256

The results obtained indicate the following vapour pressure relationship:

Log10 (Vp (Pa))=-3248.810/temp(K) + 11.991

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of 1.095

Summary

Run Log10[Vp(25oC)]
1 1.123
2 1.115
3 1.120
4 1.095
Mean 1.113
Vapour Pressure 13 Pa
Conclusions:
The vapour pressure of the test item has been determined to be 13 Pa at 25oC.
Executive summary:

The vapour pressure of the test substance (PR-4758) was measured by the effusion vapour pressure balance method in accordance with international guidelines in a GLP testing laboratory, and the value was determined to be 13 Pa at 25 deg C.

Description of key information

Vapour pressure = 13 Pa at 25°C, EU Method A4; SP Tremain & SS Atwal (2013)

Key value for chemical safety assessment

Vapour pressure:
13 Pa
at the temperature of:
25 °C

Additional information

A single key study was used to determine the vapour pressure of PR-4758. The study was conducted in accordance with EU guidelines and in accordance with GLP.