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EC number: 272-712-1 | CAS number: 68909-77-3 The residuum from the reaction of diethylene glycol and ammonia. It consists predominantly of morpholine-based derivatives such as [(aminoethoxy)ethyl]morpholine, [(hydroxyethoxy)ethyl]morpholine, 3-morpholinone, and 4,4'-(oxydi-2,1-ethanediyl)bis[morpholine].
- Life Cycle description
- Uses advised against
- Endpoint summary
- Appearance / physical state / colour
- Melting point / freezing point
- Boiling point
- Density
- Particle size distribution (Granulometry)
- Vapour pressure
- Partition coefficient
- Water solubility
- Solubility in organic solvents / fat solubility
- Surface tension
- Flash point
- Auto flammability
- Flammability
- Explosiveness
- Oxidising properties
- Oxidation reduction potential
- Stability in organic solvents and identity of relevant degradation products
- Storage stability and reactivity towards container material
- Stability: thermal, sunlight, metals
- pH
- Dissociation constant
- Viscosity
- Additional physico-chemical information
- Additional physico-chemical properties of nanomaterials
- Nanomaterial agglomeration / aggregation
- Nanomaterial crystalline phase
- Nanomaterial crystallite and grain size
- Nanomaterial aspect ratio / shape
- Nanomaterial specific surface area
- Nanomaterial Zeta potential
- Nanomaterial surface chemistry
- Nanomaterial dustiness
- Nanomaterial porosity
- Nanomaterial pour density
- Nanomaterial photocatalytic activity
- Nanomaterial radical formation potential
- Nanomaterial catalytic activity
- Endpoint summary
- Stability
- Biodegradation
- Bioaccumulation
- Transport and distribution
- Environmental data
- Additional information on environmental fate and behaviour
- Ecotoxicological Summary
- Aquatic toxicity
- Endpoint summary
- Short-term toxicity to fish
- Long-term toxicity to fish
- Short-term toxicity to aquatic invertebrates
- Long-term toxicity to aquatic invertebrates
- Toxicity to aquatic algae and cyanobacteria
- Toxicity to aquatic plants other than algae
- Toxicity to microorganisms
- Endocrine disrupter testing in aquatic vertebrates – in vivo
- Toxicity to other aquatic organisms
- Sediment toxicity
- Terrestrial toxicity
- Biological effects monitoring
- Biotransformation and kinetics
- Additional ecotoxological information
- Toxicological Summary
- Toxicokinetics, metabolism and distribution
- Acute Toxicity
- Irritation / corrosion
- Sensitisation
- Repeated dose toxicity
- Genetic toxicity
- Carcinogenicity
- Toxicity to reproduction
- Specific investigations
- Exposure related observations in humans
- Toxic effects on livestock and pets
- Additional toxicological data
Vapour pressure
Administrative data
Link to relevant study record(s)
- Endpoint:
- vapour pressure
- Type of information:
- experimental study
- Adequacy of study:
- key study
- Study period:
- 2010-10-04 - 2010-10-20
- Reliability:
- 1 (reliable without restriction)
- Rationale for reliability incl. deficiencies:
- comparable to guideline study
- Qualifier:
- equivalent or similar to guideline
- Guideline:
- EU Method A.4 (Vapour Pressure)
- GLP compliance:
- yes (incl. QA statement)
- Type of method:
- effusion method: vapour pressure balance
- Specific details on test material used for the study:
- Sponsor's identification: Amine C8
Description: dark brown liquid
Chemical name: Ethanol, 2, 2-oxybis-, reaction products with ammonia, morpholine derivs. residues
Batch number: T7-271109
Date received: 21 September 2010
Expiry date: 31 December 2011
Storage conditions: room temperature in the dark - Key result
- Temp.:
- 25 °C
- Vapour pressure:
- 0.55 Pa
- Transition / decomposition:
- no
- Conclusions:
- The vapour pressure of the test item has been determined to be 0.55 Pa at at 25 ºC.
- Executive summary:
INTRODUCTION
Hazardous physico-chemical properties of the test item have been determined. Methods employed were designed to be compatible with Commission Regulation (EC) No 440/2008 of 30 May 2008, Part A: Methods for the determination of physico-chemical properties
Method
The vapour pressure was determined using a vapour pressure balance with measurements being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using a method designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008.
Summary of Results
Run
Log10[Vp(25ºC)]
1
-0.265
2
-0.255
3
-0.256
4
-0.257
5
-0.258
6
-0.261
Mean
-0.259
Vapour Pressure
5.5 x 10-1Pa
The test item did not change in appearance under the conditions used in the determination.
Discussion
The unshaded point on run 1 has been omitted from the data analysis, because its position in relation to the other 10 points clearly indicates it is erroneous.
Conclusion
The vapour pressure of the test item has been determined to be 5.5 x 10-1Pa at 25 ºC.
Reference
Run1
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
21 |
294.15 |
0.003399626 |
248.31 |
2.483E-07 |
0.344717897 |
-0.462536169 |
22 |
295.15 |
0.003388108 |
279.46 |
2.795E-07 |
0.387962077 |
-0.411210724 |
23 |
296.15 |
0.003376667 |
312.71 |
3.127E-07 |
0.434121596 |
-0.362388609 |
24 |
297.15 |
0.003365304 |
350.35 |
3.504E-07 |
0.486375559 |
-0.313028257 |
25 |
298.15 |
0.003354016 |
390.59 |
3.906E-07 |
0.542238989 |
-0.265809259 |
26 |
299.15 |
0.003342805 |
437.31 |
4.373E-07 |
0.607098318 |
-0.216740970 |
27 |
300.15 |
0.003331667 |
488.13 |
4.881E-07 |
0.677649498 |
-0.168994879 |
28 |
301.15 |
0.003320604 |
543.65 |
5.437E-07 |
0.754725482 |
-0.122210986 |
29 |
302.15 |
0.003309614 |
605.45 |
6.055E-07 |
0.840519715 |
-0.075452095 |
30 |
303.15 |
0.003298697 |
675.64 |
6.756E-07 |
0.937961418 |
-0.027815025 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.
Slope -4294.026
Standard deviation in slope 6.934
Intercept 14.137
Standard deviation in intercept 0.023
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -4294.026/temp(K) + 14.137
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.265.
Run 1 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 1 to 6
Graph of Log10Vapour Pressure vs Reciprocal Temperature.
Run 2
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
20 |
293.15 |
0.003411223 |
237.63 |
2.376E-07 |
0.329891320 |
-0.481629111 |
21 |
294.15 |
0.003399626 |
261.59 |
2.616E-07 |
0.363153939 |
-0.439909241 |
22 |
295.15 |
0.003388108 |
291.54 |
2.915E-07 |
0.404732212 |
-0.392832229 |
23 |
296.15 |
0.003376667 |
322.69 |
3.227E-07 |
0.447976393 |
-0.348744872 |
24 |
297.15 |
0.003365304 |
357.24 |
3.572E-07 |
0.495940644 |
-0.304570298 |
25 |
298.15 |
0.003354016 |
398.18 |
3.982E-07 |
0.552775853 |
-0.257450936 |
26 |
299.15 |
0.003342805 |
443.20 |
4.432E-07 |
0.615275147 |
-0.210930627 |
27 |
300.15 |
0.003331667 |
494.42 |
4.944E-07 |
0.686381630 |
-0.163434348 |
28 |
301.15 |
0.003320604 |
547.14 |
5.471E-07 |
0.759570496 |
-0.119431913 |
29 |
302.15 |
0.003309614 |
609.74 |
6.097E-07 |
0.846475335 |
-0.072385692 |
30 |
303.15 |
0.003298697 |
679.33 |
6.793E-07 |
0.943084083 |
-0.025449585 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.
Slope -4067.764
Standard deviation in slope 26.030
Intercept 13.389
Standard deviation in intercept 0.087
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -4067.764/temp(K) + 13.389
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.255.
Run 2 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 1 to 6
Graph of Log10Vapour Pressure vs Reciprocal Temperature.
Run 3
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
20 |
293.15 |
0.003411223 |
236.43 |
2.364E-07 |
0.328225413 |
-0.483827797 |
21 |
294.15 |
0.003399626 |
261.09 |
2.611E-07 |
0.362459811 |
-0.440740140 |
22 |
295.15 |
0.003388108 |
290.74 |
2.907E-07 |
0.403621607 |
-0.394025593 |
23 |
296.15 |
0.003376667 |
321.80 |
3.218E-07 |
0.446740845 |
-0.349944339 |
24 |
297.15 |
0.003365304 |
358.64 |
3.586E-07 |
0.497884203 |
-0.302871653 |
25 |
298.15 |
0.003354016 |
397.08 |
3.971E-07 |
0.551248771 |
-0.258652366 |
26 |
299.15 |
0.003342805 |
442.51 |
4.425E-07 |
0.614317250 |
-0.211607289 |
27 |
300.15 |
0.003331667 |
492.13 |
4.921E-07 |
0.683202523 |
-0.165450539 |
28 |
301.15 |
0.003320604 |
546.64 |
5.466E-07 |
0.758876368 |
-0.119828971 |
29 |
302.15 |
0.003309614 |
605.95 |
6.060E-07 |
0.841213844 |
-0.075093589 |
30 |
303.15 |
0.003298697 |
678.44 |
6.784E-07 |
0.941848535 |
-0.026018933 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.
Slope -4067.078
Standard deviation in slope 21.916
Intercept 13.385
Standard deviation in intercept 0.074
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -4067.078/temp(K) + 13.385
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.256.
Run 3 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 1 to 6
Graph of Log10Vapour Pressure vs Reciprocal Temperature.
Run 4
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
20 |
293.15 |
0.003411223 |
236.23 |
2.362E-07 |
0.327947762 |
-0.484195329 |
21 |
294.15 |
0.003399626 |
261.09 |
2.611E-07 |
0.362459811 |
-0.440740140 |
22 |
295.15 |
0.003388108 |
289.55 |
2.896E-07 |
0.401969582 |
-0.395806809 |
23 |
296.15 |
0.003376667 |
321.30 |
3.213E-07 |
0.446046717 |
-0.350619653 |
24 |
297.15 |
0.003365304 |
357.04 |
3.570E-07 |
0.495662993 |
-0.304813505 |
25 |
298.15 |
0.003354016 |
396.38 |
3.964E-07 |
0.550276992 |
-0.259418645 |
26 |
299.15 |
0.003342805 |
440.21 |
4.402E-07 |
0.611124261 |
-0.213870475 |
27 |
300.15 |
0.003331667 |
489.63 |
4.896E-07 |
0.679731882 |
-0.167662359 |
28 |
301.15 |
0.003320604 |
543.45 |
5.435E-07 |
0.754447831 |
-0.122370786 |
29 |
302.15 |
0.003309614 |
605.45 |
6.055E-07 |
0.840519715 |
-0.075452095 |
30 |
303.15 |
0.003298697 |
674.74 |
6.747E-07 |
0.936711987 |
-0.028393922 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.
Slope -4053.160
Standard deviation in slope 22.971
Intercept 13.337
Standard deviation in intercept 0.077
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -4053.160/temp(K) + 13.337
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.257.
Run 4 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 1 to 6
Graph of Log10Vapour Pressure vs Reciprocal Temperature.
Run 5
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
20 |
293.15 |
0.003411223 |
233.93 |
2.339E-07 |
0.324754773 |
-0.488444458 |
21 |
294.15 |
0.003399626 |
261.09 |
2.611E-07 |
0.362459811 |
-0.440740140 |
22 |
295.15 |
0.003388108 |
287.95 |
2.880E-07 |
0.399748372 |
-0.398213296 |
23 |
296.15 |
0.003376667 |
320.10 |
3.201E-07 |
0.444380809 |
-0.352244705 |
24 |
297.15 |
0.003365304 |
355.94 |
3.559E-07 |
0.494135911 |
-0.306153583 |
25 |
298.15 |
0.003354016 |
395.68 |
3.957E-07 |
0.549305213 |
-0.260186280 |
26 |
299.15 |
0.003342805 |
439.31 |
4.393E-07 |
0.609874831 |
-0.214759290 |
27 |
300.15 |
0.003331667 |
489.33 |
4.893E-07 |
0.679315406 |
-0.167928536 |
28 |
301.15 |
0.003320604 |
542.35 |
5.424E-07 |
0.752920749 |
-0.123250734 |
29 |
302.15 |
0.003309614 |
608.35 |
6.084E-07 |
0.844545658 |
-0.073376866 |
30 |
303.15 |
0.003298697 |
671.35 |
6.714E-07 |
0.932005799 |
-0.030581385 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.
Slope -4074.568
Standard deviation in slope 21.543
Intercept 13.408
Standard deviation in intercept 0.072
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -4074.568/temp(K) + 13.408
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.258.
Run 5 -Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 1 to 6
Graph of Log10Vapour Pressure vs Reciprocal Temperature.
Run 6
Temperature (ºC) |
Temperature (K) |
Reciprocal Temperature (K-1) |
Mass Difference (µg) |
Mass Difference (kg) |
Vapour Pressure (Pa) |
Log10Vp |
20 |
293.15 |
0.003411223 |
234.13 |
2.341E-07 |
0.325032424 |
-0.488073314 |
21 |
294.15 |
0.003399626 |
258.00 |
2.580E-07 |
0.358170099 |
-0.445910673 |
22 |
295.15 |
0.003388108 |
280.46 |
2.805E-07 |
0.389350333 |
-0.409659449 |
23 |
296.15 |
0.003376667 |
318.90 |
3.189E-07 |
0.442714902 |
-0.353875859 |
24 |
297.15 |
0.003365304 |
353.15 |
3.532E-07 |
0.490262677 |
-0.309571168 |
25 |
298.15 |
0.003354016 |
393.78 |
3.938E-07 |
0.546667526 |
-0.262276724 |
26 |
299.15 |
0.003342805 |
438.01 |
4.380E-07 |
0.608070098 |
-0.216046353 |
27 |
300.15 |
0.003331667 |
487.34 |
4.873E-07 |
0.676552776 |
-0.169698320 |
28 |
301.15 |
0.003320604 |
541.45 |
5.415E-07 |
0.751671319 |
-0.123972021 |
29 |
302.15 |
0.003309614 |
604.05 |
6.041E-07 |
0.838576157 |
-0.076457490 |
30 |
303.15 |
0.003298697 |
669.65 |
6.697E-07 |
0.929645763 |
-0.031682506 |
A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.
Slope -4102.766
Standard deviation in slope 35.676
Intercept 13.500
Standard deviation in intercept 0.120
The results obtained indicate the following vapour pressure relationship:
Log10(Vp (Pa)) = -4102.766/temp(K) + 13.500
The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.261.
Run 6 - Graph of Log10Vapour Pressure vs Reciprocal Temperature see Attachment 3 Run 1 to 6
Graph of Log10Vapour Pressure vs Reciprocal Temperature.
Description of key information
The vapour pressure of the test substance was determined to be 0.55 Pa at 25 °C using the effusion method (vapour pressure balance) following a GLP study compatible with EC test method A.4 (Atwal et al., 2010).
Key value for chemical safety assessment
- Vapour pressure:
- 0.55 Pa
- at the temperature of:
- 25 °C
Additional information
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