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Physical & Chemical properties

Vapour pressure

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Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
From 25 March 2020 to 03 April 2020
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study
Qualifier:
according to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Version / remarks:
2008
Deviations:
no
Qualifier:
according to guideline
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Version / remarks:
2006
Deviations:
no
GLP compliance:
yes (incl. QA statement)
Remarks:
Date of Inspection: 21 August 2018, Date of Issue of Certificate: 19 November 2018
Type of method:
effusion method: vapour pressure balance
Key result
Test no.:
#1
Temp.:
25 °C
Vapour pressure:
0 Pa

The test item appeared to dry out under vaccuum determination. 


 


A total of 10 runs were started for the main sequence. Runs 5 to 10 have been deemed to have reached equilibrium and therefore utilised to show the general vapour pressure trendline and to calculate the final vapour pressure result. Runs 1 to 4 have not been utilisesd as equilibrium had not been reached.


 


The results be represent rounded values obtained by calculations based on the exact raw data.


 


Recorded temperatures, mass differences and the resulting calculated values of vapour pressure are shown in the following tables:


Run 5


Table 1 - Vapour Pressure Data


















































































































Temperature (°C)



Temperature (K)



Reciprocal Temperature (K-1)



Mass Difference (µg)



Mass Difference (kg)



Vapour Pressure (Pa)



Log10 Vp



110



383.15



0.002610



32.57



3.257e-08



0.04522



-1.34467



111



384.15



0.002603



38.29



3.829e-08



0.05316



-1.27442



112



385.15



0.002596



76.42



7.642e-08



0.10609



-0.97433



113



386.15



0.002590



49.72



4.972e-08



0.06902



-1.16103



114



387.15



0.002583



57.70



5.770e-08



0.08010



-1.09637



115



388.15



0.002576



93.97



9.397e-08



0.13045



-0.88456



116



389.15



0.002570



159.97



1.600e-07



0.22208



-0.65349



117



390.15



0.002563



150.95



1.510e-07



0.20956



-0.67869



118



391.15



0.002557



67.01



6.701e-08



0.09303



-1.03138



119



392.15



0.002550



91.82



9.182e-08



0.12747



-0.89459



120



393.15



0.002544



124.1



1.241e-07



0.17228



-0.76377




 





A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.






Slope: -7.85 x 103 


Standard error in slope:2.33 x 103


Intercept: 19.3
Standard error in intercept: 6.00




 






The results obtained indicate the following vapor pressure relationship:
Log10 (Vp (Pa)) = -7.85 x 103/temp(K) + 19.3
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -7.08.


 


Run 6


 


Table 2 - Vapour Pressure Data



 




 




















































































































Temperature (°C)



Temperature (K)



Reciprocal Temperature (K-1)



Mass Difference (µg)



Mass Difference (kg)



Vapour Pressure (Pa)



Log10 Vp



110



383.15



0.002610



44.40



4.440e-08



0.06164



-1.21014



111



384.15



0.002603



39.24



3.924e-08



0.05448



-1.26376



112



385.15



0.002596



92.41



9.241e-08



0.12829



-0.89181



113



386.15



0.002590



65.18



6.518e-08



0.09049



-1.04340



114



387.15



0.002583



69.22



6.992e-08



0.09610



-1.01728



115



388.15



0.002576



233.99



2.340e-07



0.32484



-0.48833



116



389.15



0.002570



78.27



7.827e-08



0.10866



-0.96393



117



390.15



0.002563



276.61



2.766e-07



0.38401



-0.41566



118



391.15



0.002557



117.93



1.179e-07



0.16372



-0.78590



119



392.15



0.002550



141.79



1.418e-07



0.19684



-0.70589



120



393.15



0.002544



151.66



1.517e-07



0.21054



-0.67667









A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.






Slope: -9.09 x 103 


Standard error in slope:2.88 x 103


Intercept: 22.5
Standard error in intercept: 7.43




 


The results obtained indicate the following vapor pressure relationship:
Log10 (Vp (Pa)) = -9.09 x 103/temp(K) + 22.5
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -7.92.




 


Run 7


Table 3 - Vapour Pressure Data









































































































Temperature (°C)



Temperature (K)



Reciprocal Temperature (K-1)



Mass Difference (µg)



Mass Difference (kg)



Vapour Pressure (Pa)



Log10 Vp



110



383.15



0.002610



61.11



6.111e-08



0.08484



-1.07140



111



384.15



0.002603



41.78



4.178e-08



0.05800



-1.23657



112



385.15



0.002596



69.25



6.925e-08



0.09614



-1.01710



113



386.15



0.002590



119.92



1.199e-07



0.16648



-0.77864



114



387.15



0.002583



188.97



1.890e-07



0.26234



-0.58114



115



388.15



0.002576



55.35



5.535e-08



0.07684



-1.11441



116



389.15



0.002570



169.21



1.692e-07



0.23491



-0.62910



117



390.15



0.002563



69.18



6.918e-08



0.09604



-1.01755



118



391.15



0.002557



312.41



3.124e-07



0.43371



-0.36280



120



392.15



0.002550



185.26



1.853e-07



0.25719



-0.58975







A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.






Slope: -8.83 x 103 


Standard error in slope: 3.71 x 103


Intercept: 21.9
Standard error in intercept: 9.56




 


The results obtained indicate the following vapor pressure relationship:
Log10 (Vp (Pa)) = -8.83 x 103/temp(K) + 21.9
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -7.68.




Run 8


Table 4 - Vapour Pressure Data


















































































































Temperature (°C)



Temperature (K)



Reciprocal Temperature (K-1)



Mass Difference (µg)



Mass Difference (kg)



Vapour Pressure (Pa)



Log10 Vp



110



383.15



0.002610



34.57



3.457e-08



0.04799



-1.31885



111



384.15



0.002603



76.07



7.607e-08



0.10560



-0.97634



112



385.15



0.002596



36.82



3.682e-08



0.05112



-1.29141



113



386.15



0.002590



70.07



7.007e-08



0.09728



-1.01198



114



387.15



0.002583



57.14



5.714e-08



0.07932



-1.10062



115



388.15



0.002576



56.53



5.653e-08



0.07848



-1.10524



116



389.15



0.002570



141.61



1.416e-07



0.19659



-0.70644



117



390.15



0.002563



133.62



1.336e-07



0.18550



-0.73166



118



391.15



0.002557



164.31



1.643e-07



0.22810



-0.64187



119



392.15



0.002550



191.47



1.915e-07



0.26581



-0.57543



120



392.15



0.002550



175.54



1.755e-07



0.24369



-0.61316




 


 


A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.




Slope: -1.10 x 104 


Standard error in slope: 1.95 x 103


Intercept: 27.5
Standard error in intercept: 5.01




 


The results obtained indicate the following vapor pressure relationship:
Log10 (Vp (Pa)) = -1.10 x 104/temp(K) + 27.5
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -9.49.


 


Run 9


Table 5 - Vapour Pressure Data


















































































































Temperature (°C)



Temperature (K)



Reciprocal Temperature (K-1)



Mass Difference (µg)



Mass Difference (kg)



Vapour Pressure (Pa)



Log10 Vp



110



383.15



0.002610



34.31



3.431e-08



0.04763



-1.32212



111



384.15



0.002603



60.36



6.036e-08



0.08380



-1.07676



112



385.15



0.002596



51.74



5.174e-08



0.07183



-1.14369



113



386.15



0.002590



70.91



7.091e-08



0.09844



-1.00683



114



387.15



0.002583



182.87



1.829e-07



0.25387



-0.59539



115



388.15



0.002576



41.76



4.176e-08



0.05797



-1.23680



116



389.15



0.002570



68.96



6.896e-08



0.09573



-1.01895



117



390.15



0.002563



96.66



9.666e-08



0.13419



-0.87228



118



391.15



0.002557



83.41



8.341e-08



0.11579



-0.93633



119



392.15



0.002550



93.19



9.319e-08



0.12937



-0.88817



120



392.15



0.002550



223.48



2.235e-07



0.31025



-0.50829



 


A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 9 gives the following statistical data using an unweighted least squares treatment.




Slope: -7.26 x 103 


Standard error in slope: 2.88 x 103


Intercept: 17.7
Standard error in intercept: 7.43




 


The results obtained indicate the following vapor pressure relationship:
Log10 (Vp (Pa)) = -7.26 x 103/temp(K) + 17.7
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -6.61.


Run 10


Table 6 - Vapour Pressure Data


















































































































Temperature (°C)



Temperature (K)



Reciprocal Temperature (K-1)



Mass Difference (µg)



Mass Difference (kg)



Vapour Pressure (Pa)



Log10 Vp



110



383.15



0.002610



30.90



3.090e-08



0.04290



-1.36754



111



384.15



0.002603



42.24



4.224e-08



0.05864



-1.23181



112



385.15



0.002596



31.64



3.164e-08



0.04392



-1.35734



113



386.15



0.002590



44.18



4.418e-08



0.06133



-1.21233



114



387.15



0.002583



41.58



4.158e-08



0.05772



-1.23867



115



388.15



0.002576



97.50



9.570e-08



0.13535



-0.86854



116



389.15



0.002570



77.47



7.747e-08



0.10755



-0.96839



117



390.15



0.002563



79.63



7.963e-08



0.11055



-0.95644



118



391.15



0.002557



109.69



1.097e-07



0.15228



-0.81736



119



392.15



0.002550



168.79



1.668e-07



0.23432



-0.63019



120



392.15



0.002550



172.85



1.729e-07



0.23996



-0.61986



A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 10 gives the following statistical data using an unweighted least squares treatment.




Slope: -1.18 x 104 


Standard error in slope: 1.39 x 103


Intercept: 29.3
Standard error in intercept: 3.57




 


The results obtained indicate the following vapor pressure relationship:
Log10 (Vp (Pa)) = -1.18 x 104/temp(K) + 29.3
The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -10.2.


 


Table 7 - Summary of Vapour Pressure Data






































Run



Log10 [Vp(25°C)]



5



-7.08



6



-7.92



7



-7.68



8



-9.49



9



-6.61



10



-10.2



Mean



-8.16






Conclusions:
The vapor pressure of the test item has been determined to be 6.91E-09 Pa at 25 °C.
Executive summary:



The vapor pressure of the test item has been determined to be 6.91 x 10-9 Pa at 25 °C, using the vapor pressure balance method, designed to be compatible with Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.




Description of key information

6.19 x 10-9 Pa at 25°C; OECD 104; Fox, A. J. (2020)

Key value for chemical safety assessment

Vapour pressure:
0 Pa
at the temperature of:
25 °C

Additional information