O-(ethoxycarbonyl)-N-(1-methyl-2-oxo-2-phenylethylidene)hydroxylamine

Vapour pressure

Link to relevant study record(s)

Reference

Endpoint:

vapour pressure

Type of information:

experimental study

Adequacy of study:

key study

Study period:

09 November 2017 to 13 November 2017

Reliability:

1 (reliable without restriction)

Rationale for reliability incl. deficiencies:

guideline study

Qualifier:

according to guideline

Guideline:

OECD Guideline 104 (Vapour Pressure Curve)

Version / remarks:

2006

Deviations:

no

Qualifier:

according to guideline

Guideline:

EU Method A.4 (Vapour Pressure)

Version / remarks:

2008

Deviations:

no

GLP compliance:

yes (incl. QA statement)

Type of method:

effusion method: vapour pressure balance

Key result

Temp.:

25 °C

Vapour pressure:

0.005 Pa

Run 4 Table1: Vapour Pressure Data

Temperature (ºC)		Temperature (K)		Reciprocal Temperature (K^-1)		Mass Difference (µg)		Mass Difference (kg)		Vapor Pressure (Pa)		Log10Vp
39		312.15		0.003203588		12.28		1.228E-08		0.017047786		-1.768332012
40		313.15		0.003193358		12.08		1.208E-08		0.016770135		-1.775463444
41		314.15		0.003183193		13.18		1.318E-08		0.018297217		-1.737614968
42		315.15		0.003173092		13.98		1.398E-08		0.019407822		-1.712023207
43		316.15		0.003163056		14.98		1.498E-08		0.020796078		-1.682018565
44		317.15		0.003153082		16.77		1.677E-08		0.023281056		-1.632997316
45		318.15		0.003143171		18.37		1.837E-08		0.025502266		-1.593421222
46		319.15		0.003133323		20.57		2.057E-08		0.028556430		-1.544296087

- A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope: -3.34 x 10^3

Standard error in slope: 286

Intercept: 8.91

Standard error in intercept: 0.907

- The results obtained indicate the following vapour pressure relationship:

Log10 (Vp (Pa)) = -3.34 x 10^3/temp(K) + 8.91

- The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.30.

 

Run 5 Table2: Vapor Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
39	312.15	0.003203588	11.88	1.188E-08	0.016492484	-1.782713938
40	313.15	0.003193358	12.38	1.238E-08	0.017186612	-1.764809734
42	315.15	0.003173092	14.48	1.448E-08	0.020101950	-1.696761817
43	316.15	0.003163056	15.97	1.597E-08	0.022170451	-1.654225463
44	317.15	0.003153082	16.27	1.627E-08	0.022586928	-1.646142826
45	318.15	0.003143171	19.37	1.937E-08	0.026890523	-1.570400758
46	319.15	0.003133323	21.47	2.147E-08	0.029805861	-1.525698334

- A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment:

Slope: -3.61 x 10^3

Standard error in slope: 292

Intercept: 9.78

Standard error in intercept: 0.925

- The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3.61 x 10^3/temp(K) + 9.78

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -2.34.

Run 6 Table 3: Vapour Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
39	312.15	0.003203588	12.38	1.238E-08	0.017186612	-1.764809734
40	313.15	0.003193358	12.18	1.218E-08	0.016908960	-1.771883090
41	314.15	0.003183193	13.78	1.378E-08	0.019130170	-1.718281161
42	315.15	0.003173092	15.08	1.508E-08	0.020934903	-1.679129037
43	316.15	0.003163056	15.18	1.518E-08	0.021073729	-1.676258607
44	317.15	0.003153082	16.77	1.677E-08	0.023281056	-1.632997316
45	318.15	0.003143171	19.37	1.937E-08	0.026890523	-1.570400758
46	319.15	0.003133323	19.77	1.977E-08	0.027445825	-1.561523709

- A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment:

Slope: -3.19 x 10^3

Standard error in slope: 270

Intercept: 8.43

Standard error in intercept: 0.855

- The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3.19 x 10^3/temp(K) + 8.43

- The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.26.

Run 7 Table 4: Vapour Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
39	312.15	0.003203588	12.48	1.248E-08	0.017325437	-1.761315793
40	313.15	0.003193358	12.58	1.258E-08	0.017464263	-1.757849738
41	314.15	0.003183193	13.18	1.318E-08	0.018297217	-1.737614968
42	315.15	0.003173092	12.98	1.298E-08	0.018019565	-1.744255686
43	316.15	0.003163056	15.28	1.528E-08	0.021212555	-1.673407024
44	317.15	0.003153082	16.67	1.667E-08	0.023142231	-1.635594779
45	318.15	0.003143171	18.87	1.887E-08	0.026196394	-1.581758479
46	319.15	0.003133323	21.37	2.137E-08	0.029667035	-1.527725857

- A plot of Log1 0(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment:

Slope: -3.42 x 10^3

Standard error in slope: 457

Intercept: 9.17

Standard error in intercept: 1.45

- The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3.42 x 10^3/temp(K) + 9.17

- The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.31.

Run 8 Table 5: Vapour Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
39	312.15	0.003203588	11.88	1.188E-08	0.016492484	-1.782713938
40	313.15	0.003193358	13.98	1.398E-08	0.019407822	-1.712023207
41	314.15	0.003183193	12.68	1.268E-08	0.017603089	-1.754411125
42	315.15	0.003173092	14.58	1.458E-08	0.020240775	-1.693772855
43	316.15	0.003163056	14.68	1.468E-08	0.020379601	-1.690804323
44	317.15	0.003153082	16.47	1.647E-08	0.022864580	-1.640836780
45	318.15	0.003143171	18.67	1.867E-08	0.025918743	-1.586386061
46	319.15	0.003133323	20.37	2.037E-08	0.028278779	-1.548539350

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment:

Slope: -3.09 x 10^3

Standard error in slope: 416

Intercept: 8.12

Standard error in intercept: 1.32

- The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3.09 x 10^3/temp(K) + 8.12

- The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.25.

Run 9 Table 6: Vapour Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
39	312.15	0.003203588	11.58	1.158E-08	0.016076007	-1.793821819
40	313.15	0.003193358	12.28	1.228E-08	0.017047786	-1.768332012
41	314.15	0.003183193	12.98	1.298E-08	0.018019565	-1.744255686
42	315.15	0.003173092	14.38	1.438E-08	0.019963124	-1.699771493
43	316.15	0.003163056	15.08	1.508E-08	0.020934903	-1.679129037
44	317.15	0.003153082	16.37	1.637E-08	0.022725754	-1.643481699
45	318.15	0.003143171	17.77	1.777E-08	0.024669313	-1.607842951
46	319.15	0.003133323	20.27	2.027E-08	0.028139953	-1.550676630

- A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 9 gives the following statistical data using an unweighted least squares treatment:

Slope: -3.35 x 10^3

Standard error in slope: 170

Intercept: 8.93

Standard error in intercept: 0.540

- The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3.35 x 10^3/temp(K) + 8.93

- The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.31.

 

Run 10 Table 7: Vapour Pressure Data

Temperature (ºC)	Temperature (K)	Reciprocal Temperature (K^-1)	Mass Difference (µg)	Mass Difference (kg)	Vapor Pressure (Pa)	Log10Vp
39	312.15	0.003203588	11.78	1.178E-08	0.016353658	-1.786385088
40	313.15	0.003193358	12.58	1.258E-08	0.017464263	-1.757849738
41	314.15	0.003183193	13.08	1.308E-08	0.018158391	-1.740922635
42	315.15	0.003173092	13.98	1.398E-08	0.019407822	-1.712023207
43	316.15	0.003163056	15.18	1.518E-08	0.021073729	-1.676258607
44	317.15	0.003153082	16.97	1.697E-08	0.023558708	-1.627848536
45	318.15	0.003143171	18.57	1.857E-08	0.025779918	-1.588718475
46	319.15	0.003133323	20.27	2.027E-08	0.028139953	-1.550676630

- A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 10 gives the following statistical data using an unweighted least squares treatment.

Slope: -3.40 x 10^3

Standard error in slope: 192

Intercept: 9.10

Standard error in intercept: 0.607

- The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -3.40 x 10^3/temp(K) + 9.10

- The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -2.31.

Summary of Results

- The values of vapour pressure at 25 °C extrapolated from each graph are summarised in the following table:

Table 8: Summary of Vapour Pressure Data

Run	Log10[Vp(25 ºC)]
4	-2.30
5	-2.34
6	-2.26
7	-2.31
8	-2.25
9	-2.31
10	-2.31
Mean	-2.30
Vapour Pressure	5.02 x 10^-3Pa

Discussion

- The test material did not change in appearance under the conditions used in the determination.

- A total of 10 runs were completed for the main sequence. Equilibrium with regard to vapour pressure was assessed to have been reached over the final 7 runs. Thus the final 7 runs have been used to calculate the definitive vapour pressure value for the test material.

- The results may represent rounded values obtained by calculations based on the exact raw data.

Conclusions:

Under the conditions of this study, the vapour pressure of the test material has been determined to be 5.0 x 10^-3 Pa at 25 °C.

Executive summary:

The vapour pressure of the test material was determined in accordance with the standardised guidelines OECD 104 and EU Method A.4, under GLP conditions.

The vapour pressure was determined using a vapour pressure balance. The temperature of the sample was controlled electronically.

The test material did not change in appearance under the conditions used in the determination. A total of 10 runs were completed for the main sequence. Equilibrium with regard to vapour pressure was assessed to have been reached over the final 7 runs. Thus the final 7 runs have been used to calculate the definitive vapour pressure value for the test material.

Under the conditions of this study, the vapour pressure of the test material has been determined to be 5.0 x 10^-3 Pa at 25 °C.

Description of key information

Under the conditions of this study, the vapour pressure of the test material has been determined to be 5.0 x 10^-3 at 25 °C.

Key value for chemical safety assessment

Vapour pressure:

0.005 Pa

at the temperature of:

25 °C

Additional information

The vapour pressure of the test material was determined in accordance with the standardised guidelines OECD 104 and EU Method A.4, under GLP conditions.

The vapour pressure was determined using a vapour pressure balance. The temperature of the sample was controlled electronically.

The test material did not change in appearance under the conditions used in the determination. A total of 10 runs were completed for the main sequence. Equilibrium with regard to vapour pressure was assessed to have been reached over the final 7 runs. Thus the final 7 runs have been used to calculate the definitive vapour pressure value for the test material.

Under the conditions of this study, the vapour pressure of the test material has been determined to be 5.0 x 10^-3 at 25 °C.