Registration Dossier

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Testing was conducted between 20 February 2008 and 03 March 2008.
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of relevant results.

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2008
Report Date:
2008

Materials and methods

Test guideline
Qualifier:
according to
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
yes
GLP compliance:
yes (incl. certificate)
Remarks:
Work described was performed in compliance with UK GLP standards (Schedule 1, Good Laboratory Practice Regulations 1999 (SI 1999/3106 as amended by SI 2004/0994)). Date of inspection: 21/08/2007. Date of signature: 29/04/2008
Type of method:
effusion method: vapour pressure balance

Test material

Reference
Name:
Unnamed
Type:
Constituent
Details on test material:
Sponsor's identification :Hatcol 1760
Description : clear colourless slightly viscous liquid
Purity : >99%
Date received : 04 February 2008
Storage conditions :room temperature, in the dark

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
0 Pa
Transition / decomposition
Transition / decomposition:
no

Any other information on results incl. tables

Run 1

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -7026.925
Standard deviation in slope            212.789

Intercept                                          16.320
Standard deviation in intercept           0.533

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -7026.925/temp(K) + 16.320.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.248.

Run 2

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -8784.915
Standard deviation in slope            278.657

Intercept                                          20.666
Standard deviation in intercept           0.699

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -8784.915/temp(K) + 20.666.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -8.799.

Run 3

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -8480.343
Standard deviation in slope            469.643

Intercept                                          19.878
Standard deviation in intercept           1.177

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -8480.343/temp(K) + 19.878.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -8.565.

Run 4

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -8080.251
Standard deviation in slope            238.093

Intercept                                          18.860
Standard deviation in intercept           0.598

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -8080.251/temp(K) + 18.860.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -8.242.

Run 5

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -7603.848
Standard deviation in slope            399.061

Intercept                                          17.656
Standard deviation in intercept           1.002

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -7603.848/temp(K) + 17.656.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.847.

Run 6

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -7039.013
Standard deviation in slope            313.177

Intercept                                          16.190
Standard deviation in intercept           0.786

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -7039.013/temp(K) + 16.190.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.419.

Run 7

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

Slope                                         -6714.109
Standard deviation in slope            287.395

Intercept                                          15.359
Standard deviation in intercept           0.721

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -6714.109/temp(K) + 15.359.

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -7.160.

Summary of Results

Run

Log10[Vp(25ºC)]

1

-7.248

2

-8.799

3

-8.565

4

-8.242

5

-7.847

6

-7.419

7

-7.160

Mean

-7.897

Vapour Pressure

1.268 x 10-8Pa

The test material did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:
The vapour pressure of the test material has been determined to be 1.3 x 10-8 Pa at 25ºC.
Executive summary:

Method

The vapour pressure was determined using a vapour pressure balance with measurements being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using Method A4 of Commission Directive 92/69/EEC (which constitutes Annex V of Council Directive 67/548/EEC).

Conclusion

The vapour pressure of the test material has been determined to be 1.3 x 10-8Pa at 25ºC.