Registration Dossier

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Experimental starting date: 5 January 2018 Experimental completion date: 12 January 2018
Reliability:
1 (reliable without restriction)

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2018

Materials and methods

Test guidelineopen allclose all
Qualifier:
according to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Qualifier:
according to guideline
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
GLP compliance:
yes
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Chemical structure
Reference substance name:
1,3,4-Thiadiazole-2(3H)-thione, 5-(tert-dodecyldithio)-
EC Number:
813-543-0
Cas Number:
73984-93-7
Molecular formula:
C14H26N2S4
IUPAC Name:
1,3,4-Thiadiazole-2(3H)-thione, 5-(tert-dodecyldithio)-
Test material form:
liquid
Details on test material:
- Storage: in a sealed container at room temperature
Specific details on test material used for the study:
Information as provided by the Sponsor. The Certificate of Analysis provided by the Sponsor is attached (Please see Attachment Section of this Summary).

Identification: A-153
Appearance/Physical state: pale yellow viscous liquid
Batch: B16001086
Purity: UVCB Substance (treat as 100%)
Expiry date: 01 March 2018
Storage conditions: room temperature, in the dark

Results and discussion

Vapour pressure
Key result
Temp.:
25 °C
Vapour pressure:
0 Pa

Any other information on results incl. tables

Results

Please see the Attachment Section of this report for Figures 2 to 5 Graphs of Log10Vapor Pressure vs Reciprocal Temperature Runs 2 to 5.

Recorded temperatures, mass differences and the resulting calculated values of vapor pressure are shown in the following tables:

Run 6

Table 1 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

85

358.15

0.0027921

19.20

1.920E-08

0.0266545

-1.574229

86

359.15

0.0027844

22.01

2.201E-08

0.0305555

-1.514910

87

360.15

0.0027766

22.52

2.252E-08

0.0312635

-1.504962

88

361.15

0.0027689

26.28

2.628E-08

0.0364834

-1.437905

89

362.15

0.0027613

28.99

2.899E-08

0.0402455

-1.395282

90

363.15

0.0027537

32.23

3.223E-08

0.0447435

-1.349270

91

364.15

0.0027461

35.67

3.567E-08

0.0495191

-1.305227

92

365.15

0.0027386

39.02

3.902E-08

0.0541698

-1.266243

93

366.15

0.0027311

43.16

4.316E-08

0.0599171

-1.222449

94

367.15

0.0027237

46.56

4.656E-08

0.0646372

-1.189517

95

368.15

0.0027163

52.37

5.237E-08

0.0727030

-1.138448

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

Slope:

-5.71 x 103

Standard error in slope:

113

 

Intercept:

14.4

Standard error in intercept:

0.311

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -5.71 x 103/temp(K) + 14.4

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -4.78.

Run 7

Table 2 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

85

358.15

0.0027921

18.34

1.834e-08

0.0254606

-1.594131

86

359.15

0.0027844

20.21

2.021e-08

0.0280567

-1.551964

87

360.15

0.0027766

22.27

2.227e-08

0.0309165

-1.509810

88

361.15

0.0027689

25.73

2.573e-08

0.0357198

-1.447091

89

362.15

0.0027613

27.09

2.709e-08

0.0376079

-1.424721

90

363.15

0.0027537

29.67

2.967e-08

0.0411896

-1.385213

91

364.15

0.0027461

32.30

3.230e-08

0.0448407

-1.348328

92

365.15

0.0027386

36.15

3.615e-08

0.0501855

-1.299422

93

366.15

0.0027311

42.20

4.220e-08

0.0585844

-1.232218

94

367.15

0.0027237

46.96

4.696e-08

0.0651925

-1.185802

95

368.15

0.0027163

50.30

5.030e-08

0.0698293

-1.155962

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

Slope:

-5.82 x 103

Standard error in slope:

147

 

Intercept:

14.7

Standard error in intercept:

0.405

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -5.82 x 103/temp(K) + 14.7

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -4.87.

Run 8

Table 3 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

85

358.15

0.0027921

17.21

1.721e-08

0.0238919

-1.621750

86

359.15

0.0027844

20.23

2.023e-08

0.0280844

-1.551534

87

360.15

0.0027766

22.07

2.207e-08

0.0306388

-1.513728

88

361.15

0.0027689

24.17

2.417e-08

0.0335542

-1.474254

89

362.15

0.0027613

26.11

2.611e-08

0.0362474

-1.440724

90

363.15

0.0027537

28.86

2.886e-08

0.0400651

-1.397234

91

364.15

0.0027461

33.46

3.346e-08

0.0464511

-1.333004

92

365.15

0.0027386

36.53

3.653e-08

0.0507130

-1.294881

93

366.15

0.0027311

40.73

4.073e-08

0.0565437

-1.247616

94

367.15

0.0027237

45.76

4.576e-08

0.0635266

-1.197044

95

368.15

0.0027163

49.04

4.904e-08

0.0680801

-1.166980

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.

Slope:

-5.94 x 103

Standard error in slope:

118

 

Intercept:

15.0

Standard error in intercept:

0.326

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -5.94 x 103/temp(K) + 15.0

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -4.95.

Run 9

Table 4 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

85

358.15

0.0027921

17.36

1.736e-08

0.0241001

-1.617981

86

359.15

0.0027844

20.18

2.018e-08

0.0280150

-1.552609

87

360.15

0.0027766

21.72

2.172e-08

0.0301529

-1.520671

88

361.15

0.0027689

22.66

2.266e-08

0.0314579

-1.502270

89

362.15

0.0027613

25.49

2.549e-08

0.0353867

-1.451161

90

363.15

0.0027537

28.76

2.876e-08

0.0399262

-1.398742

91

364.15

0.0027461

32.11

3.211e-08

0.0445769

-1.350890

92

365.15

0.0027386

35.53

3.553e-08

0.0493247

-1.306935

93

366.15

0.0027311

38.28

3.828e-08

0.0531424

-1.274558

94

367.15

0.0027237

43.45

4.345e-08

0.0603197

-1.219541

95

368.15

0.0027163

48.56

4.856e-08

0.0674137

-1.171252

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 9 gives the following statistical data using an unweighted least squares treatment.

Slope:

-5.75 x 103

Standard error in slope:

140

 

Intercept:

14.4

Standard error in intercept:

0.385

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -5.75 x 103/temp(K) + 14.4

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -4.85.

Run 10

Table 4 – Vapor Pressure Data

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

85

358.15

0.0027921

17.32

1.732e-08

0.0240446

-1.618982

86

359.15

0.0027844

18.89

1.889e-08

0.0262242

-1.581298

87

360.15

0.0027766

20.91

2.091e-08

0.0290284

-1.537176

88

361.15

0.0027689

23.53

2.353e-08

0.0326657

-1.485908

89

362.15

0.0027613

26.25

2.625e-08

0.0364417

-1.438401

90

363.15

0.0027537

28.90

2.890e-08

0.0401206

-1.396633

91

364.15

0.0027461

31.76

3.176e-08

0.0440910

-1.3556450

92

365.15

0.0027386

34.38

3.438e-08

0.0477282

-1.321225

93

366.15

0.0027311

40.22

4.022e-08

0.0558357

-1.253088

94

367.15

0.0027237

42.50

4.250e-08

0.0590009

-1.229141

95

368.15

0.0027163

48.30

4.830e-08

0.0670528

-1.173583

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 10 gives the following statistical data using an unweighted least squares treatment.

Slope:

-5.87 x 103

Standard error in slope:

88.9

 

Intercept:

14.8

Standard error in intercept:

0.245

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -5.87 x 103/temp(K) + 14.8

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -4.92.

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

Table 5            Summary of Vapor Pressure Data

Run

Log10[Vp(25 ºC)]

6

-4.78

7

-4.87

8

-4.95

9

-4.85

10

-4.92

Mean

-4.87

 Vapor Pressure   

1.34 x 10 -5Pa

The test item did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:
The vapor pressure of the test item has been determined to be 1.3 x 10-5 Pa at 25 ºC.
Executive summary:

The determination was carried out using a procedure designed to be compatible with Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Conclusion

The vapor pressure of the test item has been determined to be 1.3 x 10 -5Pa at 25 ºC.