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Diss Factsheets

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Experimental Starting Date: 19 August 2014 Completion Date: 28 August 2014
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: see 'Remark'
Remarks:
Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of the relevant results. The study report was conclusive, done to a valid guideline and the study was conducted under GLP conditions.

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2014
Report date:
2014

Materials and methods

Test guideline
Qualifier:
according to guideline
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Deviations:
no
GLP compliance:
yes
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Reference substance name:
NACET10419
IUPAC Name:
NACET10419
Constituent 2
Reference substance name:
1450841-11-8 (planer)
IUPAC Name:
1450841-11-8 (planer)
Test material form:
other: Clear colorless liquid
Details on test material:
Common/Commercial Name: NACET10419
Chemical Name: (6S)-Allyl 2,2,6-trimethylcyclohexanecarboxylate
CAS Number: 1450841-11-8 (planer)
Appearance/Physical State: Clear colorless liquid
Batch: KU31213
Purity: 100%
Expiry Date: 20 December 2015
Storage Conditions: Room temperature in the dark

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
11 Pa
Transition / decomposition
Transition / decomposition:
no

Any other information on results incl. tables

Results

Recorded temperatures, mass differences and the resulting calculated values of vapour pressure are shown in the following tables:

 

Run 1

 

Table 3.1– Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

128.72

1.287E-07

0.178696338

-0.747884348

-9

264.15

0.003785728

151.50

1.515E-07

0.210320814

-0.677117746

-8

265.15

0.003771450

183.40

1.834E-07

0.254606187

-0.594131047

-7

266.15

0.003757280

204.76

2.048E-07

0.284259339

-0.546285258

-6

267.15

0.003743215

232.25

2.323E-07

0.322422502

-0.491574656

-5

268.15

0.003729256

260.69

2.607E-07

0.361904508

-0.441406007

-4

269.15

0.003715400

298.78

2.988E-07

0.414783187

-0.382178856

-3

270.15

0.003701647

335.16

3.352E-07

0.465287948

-0.332278197

-2

271.15

0.003687996

382.56

3.826E-07

0.531091291

-0.274830820

-1

272.15

0.003674444

424.10

4.241E-07

0.588759454

-0.230062106

0

273.15

0.003660992

482.78

4.828E-07

0.670222328

-0.173781108

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-4.02 x 103

Standard error in slope:

74.1

Intercept:

14.6

Standard error in intercept:

0.276

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) =-4.02 x 103/temp(K) + 14.6

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 1.07.

Run 2

 

Table 3.2 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

128.95

1.290E-07

0.179015637

-0.747109032

-9

264.15

0.003785728

148.74

1.487E-07

0.206489227

-0.685102602

-8

265.15

0.003771450

174.45

1.745E-07

0.242181294

-0.615859405

-7

266.15

0.003757280

199.88

1.999E-07

0.277484649

-0.556761038

-6

267.15

0.003743215

226.43

2.264E-07

0.314342851

-0.502596412

-5

268.15

0.003729256

260.35

2.604E-07

0.361432501

-0.441972797

-4

269.15

0.003715400

298.67

2.987E-07

0.414630479

-0.382338777

-3

270.15

0.003701647

332.69

3.327E-07

0.461858955

-0.335490632

-2

271.15

0.003687996

371.21

3.712E-07

0.515334583

-0.287910712

-1

272.15

0.003674444

420.34

4.203E-07

0.583539611

-0.233929659

0

273.15

0.003660992

475.02

4.750E-07

0.659449459

-0.180818483

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-4.04 x 103

Standard error in slope:

53.4

Intercept:

14.6

Standard error in intercept:

0.199

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -4.04 x 103/temp(K) + 14.6

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 1.07.

Run 3

 

Table 3.3 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

131.70

1.317E-07

0.182833341

-0.737944604

-9

264.15

0.003785728

148.76

1.488E-07

0.206516992

-0.685044209

-8

265.15

0.003771450

177.56

1.776E-07

0.246498771

-0.608185242

-7

266.15

0.003757280

198.92

1.989E-07

0.276151923

-0.558851928

-6

267.15

0.003743215

230.11

2.301E-07

0.319451634

-0.495594886

-5

268.15

0.003729256

255.52

2.555E-07

0.354727224

-0.450105480

-4

269.15

0.003715400

290.08

2.901E-07

0.402705358

-0.395012592

-3

270.15

0.003701647

326.66

3.267E-07

0.453487770

-0.343434421

-2

271.15

0.003687996

375.17

3.752E-07

0.520832078

-0.283302275

-1

272.15

0.003674444

418.74

4.187E-07

0.581318401

-0.235585930

0

273.15

0.003660992

472.06

4.721E-07

0.655340221

-0.183533177

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-3.97 x 103

Standard error in slope:

45.6

Intercept:

14.4

Standard error in intercept:

0.170

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.97 x 103/temp(K) + 14.4

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 1.04.

Run 4

 

Table 3.4 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

132.50

1.325E-07

0.183943946

-0.735314500

-9

264.15

0.003785728

155.85

1.559E-07

0.216359729

-0.664823572

-8

265.15

0.003771450

175.99

1.760E-07

0.244319208

-0.612042387

-7

266.15

0.003757280

201.57

2.016E-07

0.279830802

-0.553104483

-6

267.15

0.003743215

228.51

2.285E-07

0.317230424

-0.498625168

-5

268.15

0.003729256

260.34

2.603E-07

0.361418619

-0.441989478

-4

269.15

0.003715400

290.78

2.908E-07

0.403677137

-0.393965847

-3

270.15

0.003701647

329.89

3.299E-07

0.457971837

-0.339161228

-2

271.15

0.003687996

374.06

3.741E-07

0.519291114

-0.284589109

-1

272.15

0.003674444

415.83

4.158E-07

0.577278575

-0.238614560

0

273.15

0.003660992

470.39

4.704E-07

0.653021833

-0.185072298

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-3.90 x 103

Standard error in slope:

35.2

Intercept:

14.1

Standard error in intercept:

0.131

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -3.90 x 103/temp(K) + 14.1

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 1.02.

Run 5

 

Table 3.5 – Vapor Pressure Data

 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10Vp

-10

263.15

0.003800114

129.61

1.296E-07

0.179931886

-0.744891868

-9

264.15

0.003785728

146.82

1.468E-07

0.203823775

-0.690745159

-8

265.15

0.003771450

176.48

1.765E-07

0.244999454

-0.610834884

-7

266.15

0.003757280

199.14

1.991E-07

0.276457339

-0.558371876

-6

267.15

0.003743215

226.79

2.268E-07

0.314842623

-0.501906478

-5

268.15

0.003729256

255.77

2.558E-07

0.355074288

-0.449680775

-4

269.15

0.003715400

292.77

2.928E-07

0.406439767

-0.391003806

-3

270.15

0.003701647

328.05

3.281E-07

0.455417446

-0.341590337

-2

271.15

0.003687996

368.13

3.681E-07

0.511058754

-0.291529168

-1

272.15

0.003674444

417.52

4.175E-07

0.579624728

-0.236853095

0

273.15

0.003660992

470.39

4.704E-07

0.653021833

-0.185072298

 

A plot of Log10(vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

 

Slope:

-4.00 x 103

Standard error in slope:

52.5

Intercept:

14.5

Standard error in intercept:

0.196

 

The results obtained indicate the following vapor pressure relationship:

 

Log10(Vp (Pa)) = -4.00 x 103/temp(K) + 14.5

 

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of 1.05.

Please see the Graphs of Log10Vapor Pressure vs Reciprocal Temperature Runs 1 -5 in Attachment 2 of this Summary.

Summary of Results

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

 

Table 3.6 – Summary of Vapor Pressure Data

 

Run

Log10[Vp(25 ºC)]

1

1.07

2

1.07

3

1.04

4

1.02

5

1.05

Mean

1.05

Vapor Pressure

11.2 Pa

 

The test item did not change in appearance under the conditions used in the determination.

Applicant's summary and conclusion

Conclusions:
The vapor pressure of the test item has been determined to be 11 Pa at 25 ºC.
Executive summary:

The determination was carried out using a procedure designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Summary of Results

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

 

Table 3.6 – Summary of Vapor Pressure Data

 

Run

Log10[Vp(25 ºC)]

1

1.07

2

1.07

3

1.04

4

1.02

5

1.05

Mean

1.05

Vapor Pressure

11.2 Pa

 

The test item did not change in appearance under the conditions used in the determination.

Conclusion

The vapor pressure of the test item has been determined to be 11 Pa at 25 ºC.