1,2,3,4,4a,7,8,8a-octahydro-2,4a,5,8a-tetramethyl-1-naphthyl formate

Vapour pressure

Link to relevant study record(s)

Reference

Endpoint:

vapour pressure

Type of information:

experimental study

Adequacy of study:

key study

Study period:

The study was conducted between 19 May 2014 and 21 May 2014.

Reliability:

1 (reliable without restriction)

Rationale for reliability incl. deficiencies:

other: GLP guideline study.

Qualifier:

according to guideline

Guideline:

OECD Guideline 104 (Vapour Pressure Curve)

Deviations:

no

Qualifier:

according to guideline

Guideline:

EU Method A.4 (Vapour Pressure)

Deviations:

no

GLP compliance:

yes (incl. QA statement)

Type of method:

effusion method: vapour pressure balance

Specific details on test material used for the study:

Batch: SC00010054
Purity: 96.5%

Temp.:

25 °C

Vapour pressure:

0.64 Pa

Key result

Temp.:

20 °C

Vapour pressure:

0.36 Pa

Remarks on result:

other: Calculated from the study raw data.

Recorded temperatures, mass differences and the resulting calculated values of vapour pressure are shown in the following tables.

 

Vapour pressure data: Run 1.

Temperature (°C)	Temperature (K)	Reciprocal temperature (K^-1)	Mass difference (µg)	Mass difference (kg)	Vapour pressure (Pa)	Log10 Vp
20	293.15	0.003411223	257.15	2.572E-07	0.356990081	-0.447343850
21	294.15	0.003399626	288.48	2.885E-07	0.400484148	-0.397414669
22	295.15	0.003388108	320.55	3.206E-07	0.445005524	-0.351634598
23	296.15	0.003376667	355.99	3.560E-07	0.494205324	-0.306092580
24	297.15	0.003365304	401.87	4.019E-07	0.557898519	-0.253444792
25	298.15	0.003354016	445.46	4.455E-07	0.618412606	-0.208721666
26	299.15	0.003342805	500.04	5.000E-07	0.694183630	-0.158525632
27	300.15	0.003331667	564.22	5.642E-07	0.783281912	-0.106081902
28	301.15	0.003320604	641.65	6.417E-07	0.89774590	-0.050232180
29	302.15	0.003309614	698.95	6.990E-07	0.970321670	-0.013084270
30	303.15	0.00328697	781.62	7.816E-07	10.85088810	-0.035465285

 

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope: -4.32E+03

Standard error in slope: 36.5

Intercept: 14.3

Standard error in intercept: 0.122

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4.32E+03 / temp (K) + 14.3

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.204.

 

Vapour pressure data: Run 2.

Temperature (°C)	Temperature (K)	Reciprocal temperature (K^-1)	Mass difference (µg)	Mass difference (kg)	Vapour pressure (Pa)	Log10 Vp
20	293.15	0.003411223	262.98	2.630E-07	0.365083615	-0.437607658
21	294.15	0.003399626	296.83	2.968E-07	0.412076087	-0.385022587
22	295.15	0.003388108	335.89	3.359E-07	0.466301375	-0.331333304
23	296.15	0.003376667	369.42	3.694E-07	0.512849605	-0.290009975
24	297.15	0.003365304	412.38	4.124E-07	0.572489091	-0.242232784
25	298.15	0.003354016	464.88	4.649E-07	0.645372542	-0.190189516
26	299.15	0.003342805	523.06	5.281E-07	0.733082568	-0.134847107
27	300.15	0.003331667	579.66	5.797E-07	0.804716588	-0.094357046
28	301.15	0.003320604	642.17	6.422E-07	0.891496483	-0.049880366
29	302.15	0.003309614	720.20	7.202E-07	0.999822114	-0.000077262
30	303.15	0.003298697	807.36	8.074E-07	1.120822524	0.049536850

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope: -4.30E+03

Standard error in slope: 30.5

Intercept: 14.2

Standard error in intercept: 0.102

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4.30E+03 / temp (K) + 14.2

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.190.

 

Vapour pressure data: Run 3.

Temperature (°C)	Temperature (K)	Reciprocal temperature (K^-1)	Mass difference (µg)	Mass difference (kg)	Vapour pressure (Pa)	Log10 Vp
20	293.15	0.003411223	258.74	2.587E-07	0.359194409	-0.444666805
21	294.15	0.003399626	296.78	2.968 E-07	0.412006675	-0.385095748
22	295.15	0.003388108	329.99	3.300 E-07	0.458110663	-0.339029599
23	296.15	0.003376667	368.70	3.687 E-07	0.511850060	-0.290857241
24	297.15	0.003365304	407.80	4.078 E-07	0.566130878	-0.247083157
25	298.15	0.003354016	459.49	4.595 E-07	0.637889841	-0.195254315
26	299.15	0.003342805	527.96	5.280 E-07	0.732943743	-0.134929359
27	300.15	0.003331667	572.76	5.728 E-07	0.795137620	-0.099557698
28	301.15	0.003320604	643.50	6.435 E-07	0.893342864	-0.048981827
29	302.15	0.003309614	713.93	7.139 E-07	0.991117748	-0.003874747
30	303.15	0.0032989697	786.54	7.865 E-07	1.091919030	0.038190435

 

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope: -4.29E+03

Standard error in slope: 42.3

Intercept: 14.2

Standard error in intercept: 0.142

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4.29E+03 / temp (K) + 14.2

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.194.

 

Vapour pressure data: Run 4.

Temperature (°C)	Temperature (K)	Reciprocal temperature (K^-1)	Mass difference (µg)	Mass difference (kg)	Vapour pressure (Pa)	Log10 Vp
20	293.15	0.003411223	258.25	2.583 E-07	0.358517163	-0.445490049
21	294.15	0.003399626	290.55	2.906 E-07	0.406657838	-0.394309499
22	295.15	0.003388108	323.27	3.233 E-07	0.44878581	-0.347964976
23	296.15	0.003376667	356.32	3.563 E-07	0.494663449	-0.305690179
24	297.15	0.003365304	392.21	3.922 E-07	0.544487964	-0.264011716
25	298.15	0.003354016	442.49	4.425 E-07	0.614289485	-0.211626918
26	299.15	0.003342805	524.29	5.243 E-07	0.727848842	-0.137958804
27	300.15	0.003331667	544.12	5.441 E-07	0.755377963	-0.121835689
28	301.15	0.003320604	599.16	5.992 E-07	0.831787584	-0.079987567
29	302.15	0.003309614	669.12	6.691 E-07	0.928909988	-0.032026368
30	303.15	0.0032989697	762.71	7.627 E-07	1.058836885	0.024829062

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope: -4.12E+03

Standard error in slope: 84.1

Intercept: 13.6

Standard error in intercept: 0.282

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4.12E+03 / temp (K) + 13.6

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.209.

 

Vapour pressure data: Run 5.

Temperature (°C)	Temperature (K)	Reciprocal temperature (K^-1)	Mass difference (µg)	Mass difference (kg)	Vapour pressure (Pa)	Log10 Vp
20	293.15	0.003411223	251.97	2.520E-07	0.349798914	-0.456181543
21	294.15	0.003399626	289.17	2.892 E-07	0.401442045	-0.396377144
22	295.15	0.003388108	326.96	3.270 E-07	0.453904247	-0.343035754
23	296.15	0.003376667	366.57	3.666 E-07	0.508893075	-0.293373459
24	297.15	0.003365304	408.63	4.086 E-07	0.567283130	-0.246200131
25	298.15	0.003354016	455.32	4.553 E-07	0.632100812	-0.199213652
26	299.15	0.003342805	511.78	5.118 E-07	0.710481757	-0.148447069
27	300.15	0.003331667	573.82	5.738 E-07	0.796609172	-0.098754698
28	301.15	0.003320604	652.71	6.527 E-07	0.906128703	-0.042810112
29	302.15	0.003309614	716.81	7.168 E-07	0.995115926	-0.002126323
30	303.15	0.0032989697	804.54	8.045 E-07	1.116907642	0.048017262

 

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

Slope: -4.43E+03

Standard error in slope: 31.6

Intercept: 14.7

Standard error in intercept: 0.106

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4.43E+03 / temp (K) + 14.7

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.196.

 

Vapour pressure data: Run 7.

Temperature (°C)	Temperature (K)	Reciprocal temperature (K^-1)	Mass difference (µg)	Mass difference (kg)	Vapour pressure (Pa)	Log10 Vp
21	294.15	0.003399626	289.99	2.900E-07	0.402580415	-0.395147357
22	295.15	0.003388108	328.49	3.285 E-07	0.456028279	-0.341008226
23	296.15	0.003376667	366.92	3.669 E-07	0.509378964	-0.292958994
24	297.15	0.003365304	414.81	4.148 E-07	0.575862554	-0.239681161
25	298.15	0.003354016	462.54	4.625 E-07	0.642124022	-0.192381083
26	299.15	0.003342805	531.24	5.312 E-07	0.737497223	-0.132239611
27	300.15	0.003331667	586.96	5.870 E-07	0.814850858	-0.088921873
28	301.15	0.003320604	652.12	6.521 E-07	0.905309632	-0.043202859
29	302.15	0.003309614	733.12	7.331 E-07	1.017758384	0.007644689
30	303.15	0.0032989697	808.88	8.089 E-07	1.122932674	0.050353719

 

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

Slope: -4.44E+03

Standard error in slope: 37.2

Intercept: 14.7

Standard error in intercept: 0.125

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4.44E+03 / temp (K) + 14.7

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.190.

 

Vapour pressure data: Run 8.

Temperature (°C)	Temperature (K)	Reciprocal temperature (K^-1)	Mass difference (µg)	Mass difference (kg)	Vapour pressure (Pa)	Log10 Vp
20	293.15	0.003411223	251.11	2.511E-07	0.348605014	-0.457666371
21	294.15	0.003399626	293.73	2.937 E-07	0.0.407772493	-0.389582073
22	295.15	0.003388108	336.93	3.369 E-07	0.467745161	-0.329990697
23	296.15	0.003376667	372.53	3.725 E-07	0.517167082	-0.286369126
24	297.15	0.003365304	416.33	4.163 E-07	0.577972703	-0.238092672
25	298.15	0.003354016	466.66	4.667 E-07	0.647843638	-0.188629802
26	299.15	0.003342805	525.93	5.259 E-07	0.730125583	-0.136602434
27	300.15	0.003331667	595.16	5.952 E-07	0.826234559	-0.082896644
28	301.15	0.003320604	656.48	6.565 E-07	0.911362429	-0.040308879
29	302.15	0.003309614	747.40	7.474 E-07	1.037582683	0.016022715
30	303.15	0.0032989697	821.25	8.213 E-07	1.140405403	0.056954004

 

A plot of Log10 (vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.

Slope: -4.50E+03

Standard error in slope: 53.6

Intercept: 14.9

Standard error in intercept: 0.180

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -4.50E+03 / temp (K) + 14.9

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -0.187.

 

Summary of results

The values of vapour pressure at 25°C extrapolated from each graph are summarised in the following table:

Summary of vapour pressure data

Run	Log10[VP (25°C)]
1	-0.204
2	-0.190
3	-0.194
4	-0.209
5	-0.196
6	-0.190
7	-0.187
Mean	-0.196
Vapour pressure	0.637 Pa

The test item did not change in appearance under the conditions used in the determination.

Run 6 was not used as one of the points was over the maximum operating limit meaning the run stopped automatically.

Conclusions:

The vapour pressure of the test item has been determined to be 0.64 Pa at 25 °C.

Executive summary:

The vapour pressure of Oxyoctaline Formate has been determined to be 0.64 Pa at 25°C, using the vapour pressure balance method, designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) NO 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Description of key information

The vapour pressure of Oxyoctaline Formate has been determined to be 0.64 Pa at 25°C, using the vapour pressure balance method, designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) NO 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006. The vapour pressure of Oxyoctaline Formate has been calculated from the study raw data to be 0.36 Pa at 20°C.

Key value for chemical safety assessment

Vapour pressure:

0.36 Pa

at the temperature of:

20 °C

Additional information

The vapour pressure of Oxyoctaline Formate was determined using the vapour pressure balance method, designed to be compatible with Method A4 Vapour Pressure of Commission Regulation (EC) NO 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006. The test item did not change in appearance under the conditions used in the determination and the vapour pressure was determined to be 0.64 Pa at 25°C.