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Diss Factsheets

Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2018
Report date:
2018

Materials and methods

Test guidelineopen allclose all
Qualifier:
equivalent or similar to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Version / remarks:
2008
Qualifier:
equivalent or similar to guideline
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Version / remarks:
2006
GLP compliance:
yes (incl. QA statement)
Remarks:
MHRA
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Chemical structure
Reference substance name:
ε-Caprolactone, oligomers, esters with acrylic acid and 2,2,2',2'-tetrakis (hydroxymethyl)-3,3'-oxydipropan-1-ol
EC Number:
500-276-7
EC Name:
ε-Caprolactone, oligomers, esters with acrylic acid and 2,2,2',2'-tetrakis (hydroxymethyl)-3,3'-oxydipropan-1-ol
Cas Number:
89800-10-2
Molecular formula:
{(C10H16O7).(C3H3O)b.[(C6H10O2)m.(C3H3O)a]} (i.e., UVCB substance)
IUPAC Name:
ε-Caprolactone, oligomers, esters with acrylic acid and 2,2,2',2'-tetrakis (hydroxymethyl)-3,3'-oxydipropan-1-ol
Test material form:
liquid
Details on test material:
Colorless to light yellow

Results and discussion

Vapour pressure
Key result
Temp.:
25 °C
Vapour pressure:
0 Pa

Any other information on results incl. tables

Recorded temperatures, mass differences and the resulting calculated values of vapor pressure are shown in the following tables:

Table 1 – Vapor Pressure Data for Run 5

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (μg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10 Vp

80

353.15

0.0028317

7.94

7.940e-09

0.0110228

-1.957710

81

354.15

0.0028237

9.59

9.590e-09

0.0133134

-1.875712

82

355.15

0.0028157

10.05

1.005e-08

0.0139520

-1.855364

83

356.15

0.0028078

10.65

1.065e-08

0.0147849

-1.830181

84

357.15

0.0027999

11.25

1.125e-08

0.0156179

-1.806378

85

358.15

0.0027921

11.75

1.175e-08

0.0163120

-1.787493

86

359.15

0.0027844

11.62

1.162e-08

0.0161315

-1.792324

87

360.15

0.0027766

12.70

1.270e-08

0.0176309

-1.753727

88

361.15

0.0027689

13.22

1.322e-08

0.0183528

-1.736299

89

362.15

0.0027613

13.54

1.354e-08

0.0187970

-1.725912

90

363.15

0.0027537

14.40

1.440e-08

0.0199909

-1.699168

 

A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

Slope:

-2.82 x 103

Standard error in slope:

240

Intercept:

6.07

Standard error in intercept:

0.669

 

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -2.82 x 103/ temp (K) + 6.07

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -3.39.

Table 2 – Vapor Pressure Data for Run 6

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (μg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10 Vp

80

353.15

0.0028317

7.30

7.300e-09

0.0101343

-1.994208

81

354.15

0.0028237

7.74

7.740e-09

0.0107451

-1.968789

82

355.15

0.0028157

8.12

8.120e-09

0.0112726

-1.947974

83

356.15

0.0028078

6.61

6.610e-09

0.0091764

-2.037329

84

357.15

0.0027999

8.63

8.630e-09

0.0119807

-1.921520

85

358.15

0.0027921

9.05

9.050e-09

0.0125637

-1.900882

86

359.15

0.0027844

9.84

9.840e-09

0.0136604

-1.864535

87

360.15

0.0027766

10.14

1.014e-08

0.0140769

-1.851492

88

361.15

0.0027689

10.32

1.032e-08

0.0143268

-1.843851

89

362.15

0.0027613

11.05

1.105e-08

0.0153402

-1.814168

90

363.15

0.0027537

11.15

1.115e-08

0.0154791

-1.810256

 

A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

Slope:

-2.66 x 103

Standard error in slope:

407

Intercept:

5.51

Standard error in intercept:

1.14

 

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -2.66 x 103/ temp (K) + 5.51

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -3.40.

Table 3 – Vapor Pressure Data for Run 7 

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (μg)

Mass Difference (kg)

Vapor Pressure (Pa)

Log10 Vp

80

353.15

0.0028317

6.38

6.380e-09

0.0088571

-2.052710

81

354.15

0.0028237

6.47

6.470e-09

0.0089820

-2.046626

82

355.15

0.0028157

7.13

7.130e-09

0.0098983

-2.004441

83

356.15

0.0028078

6.20

6.200e-09

0.0086072

-2.065139

84

357.15

0.0027999

7.81

7.810e-09

0.0108423

-1.964879

85

358.15

0.0027921

8.15

8.150e-09

0.0113143

-1.946373

86

359.15

0.0027844

8.86

8.860e-09

0.012300

-1.910097

87

360.15

0.0027766

9.49

9.490e-08

0.0131746

-1.880264

88

361.15

0.0027689

9.35

9.350e-08

0.0129802

-1.886719

89

362.15

0.0027613

9.77

9.770e-08

0.0135633

-1.867636

90

363.15

0.0027537

10.81

1.081e-08

0.0150071

-1.823705

 

A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighted least squares treatment.

Slope:

-3.08 x 103

Standard error in slope:

323

Intercept:

6.64

Standard error in intercept:

0.902

 

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -3.08 x 103/ temp (K) + 6.64

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -3.68.

Table 4 – Vapor Pressure Data for Run 8

Temperature (ºC)

Temperature (K)

ReciprocalTemperature (K-1)

Mass Difference (μg)

Mass Difference (kg)

VaporPressure (Pa)

Log10Vp

80

353.15

0.0028317

6.11

6.110e-09

0.0084822

-2.071489

81

354.15

0.0028237

6.38

6.380e-09

0.0088571

-2.052710

82

355.15

0.0028157

7.22

7.220e-09

0.0100232

-1.998993

83

356.15

0.0028078

6.58

6.580e-09

0.0091347

-2.039304

84

357.15

0.0027999

7.47

7.470e-09

0.0103703

-1.984210

85

358.15

0.0027921

7.99

7.990e-09

0.0110922

-1.954984

86

359.15

0.0027844

8.06

8.060e-09

0.0111893

-1.951195

87

360.15

0.0027766

8.13

8.130e-09

0.0112865

-1.947440

88

361.15

0.0027689

8.94

8.940e-09

0.0124110

-1.906193

89

362.15

0.0027613

9.52

9.520e-09

0.0132162

-1.878893

 

A plot of Log10 (vapor pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighted least squares treatment.

Slope:

-2.57 x 103

Standard error in slope:

250

Intercept:

5.19

Standard error in intercept:

0.699

 

The results obtained indicate the following vapor pressure relationship:

Log10(Vp (Pa)) = -2.57 x 103/ temp (K) + 5.19

The above yields a vapor pressure (Pa) at 298.15 K with a common logarithm of -3.41.

 

The values of vapor pressure at 25 °C extrapolated from each graph are summarized in the following table:

Table5 - Summary of Vapor Pressure Data

Run

Log10 [Vp(25 ºC)]

5

-3.39

6

-3.40

7

-3.68

8

-3.41

Mean

-3.47

Vapor Pressure

3.41 x 10-4 Pa

 

Discussion

A total of 8 runs were completed for the main sequence. Equilibrium with regard to vapor pressure was assessed to have been reached over the final 4 runs. Thus, the final 4 runs were used to calculate the definitive vapor pressure value for the test item. 

The test item changed to a clear colorless solid mass under the conditions used in the determination.

The nature of the test item makes this unavoidable due to the potential removal of an inhibitor. Readings were taken at the lowest possible temperature that allowed multiple runs to display equilibrium prior to the sample fully solidifying.

The results may represent rounded values obtained by calculations based on the exact raw data.

 

Conclusion

The vapor pressure of the test item has been determined to be 3.4 x 10-4 Pa at 25 ºC.

Applicant's summary and conclusion